Nickel has a face-centered cubic unit cell. The density of nickel is 6.84 g/cm³. Calculate a value for the atomic radius of nickel. l = 2.828 fcc = y atoms. d=6:8491cm³ V=l³ rearrange may be? l=218280 Find li V = m Matams Ni. E I need to use ・this formula for radius.. 3,898 x 10-22 6.8461cm ³ 1. mul 6.022x1023 and final answers were r=136pm ·and I = 3.85 x 1.0=8cm from the text book. .a.toms 2g ŀ: 2.828 = -5.83x10-23. 3. .cm. 58.69 g/mol 1.mol 3.898 g Ni X10-22
Nickel has a face-centered cubic unit cell. The density of nickel is 6.84 g/cm³. Calculate a value for the atomic radius of nickel. l = 2.828 fcc = y atoms. d=6:8491cm³ V=l³ rearrange may be? l=218280 Find li V = m Matams Ni. E I need to use ・this formula for radius.. 3,898 x 10-22 6.8461cm ³ 1. mul 6.022x1023 and final answers were r=136pm ·and I = 3.85 x 1.0=8cm from the text book. .a.toms 2g ŀ: 2.828 = -5.83x10-23. 3. .cm. 58.69 g/mol 1.mol 3.898 g Ni X10-22
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter9: Liquids And Solids
Section: Chapter Questions
Problem 60QAP: Aluminum metal crystallizes with a face-centered cubic unit cell. The volume of the cell is 0.0662...
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Hello I need help with this problem. I tried solving it, but i couldnt figure it out, i provided the correct answers. the problem is that the formula im being asked to use for radius is the one i added below, so i have to get that answer using that, can u plz explain it. thanks much!
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