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- Questão 10A certain hydrocarbon had the molecular formula C16H26 and contained two triple bonds. Ozonolysis resulted in CH3(CH2)4CO2H and HO2CCH2CH2CO2H as the only products. What is the reasonable structure for this hydrocarbon? Hexadec-6,10-dino undec-1,5-dino Hept-1,5-dino hex-1,5-dino nahThe most stable carbocation among the following is CH,O · CH, CH, - CH, NO, CH, CH,H3C CH3 H3C NA C→XT Br Br₂ CH₂Cl₂ H3C Electrophilic addition of bromine, Br₂, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH₂Cl₂. CH3 Br In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions Br CH3 H3C CH3
- An alkene having the molecular formula C5H10 is treated sequentially with ozone (O3) and zinc/acetic acid to give the product/s shown. H3C O CH3CHCH + H. Draw a structural formula for the alkene. You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. In cases where there is more than one answer, just draw one. P opy aste [* Previous NextCH3 CH3 Br- Br2 .CH3 CH2Cl2 CH3 H3C H3C Br Electrophilic addition of bromine, Brɔ, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH,Cl,. In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions CH3 CH3 CH3 CH3 H3C H3C :Br: :Br:The rate of hydration of 2-butene and 2-methylpropene differ by several orders of magnitude. Whcih alkene is more rapidly hydrated and why?
- When an unsymmetrical alkene such as propene is treated with N-bromosuccinimide in aqueous dimethyl sulfoxide, the major product has the bromine atom bonded to the less highly substituted carbon atom. Is this Markovnikov or non-Markovnikov orientation? Show its reaction mechanism. OH Brz, H,O CH;CH=CH, CH;CHCH,Br What products would you expect from oxymercuration-demercuration of 1-hexene? Show the reaction mechanism. 1.Hg(AOc), H,0 CH;CH,CH,CH,CH=CH; 2. NaBH, hex-1-eneHow many alkene products are possible in the following reaction? CI CH3 NaOEt {"CH3 HDraw a structural formula for the product formed upon hydroboration/oxidation of the alkene below. CH3CH2 C=CH2 CH3CH2 Use wedge and hash bonds ONLY for rings. Do not show stereochemistry in other cases. • If the reaction produces a racemic mixture, just draw one stereoisomer. C P opy aste ○, [片
- When 2-pentene is treated with Cl, in methanol, three products are formed. Account for the formation of each product (you need not explain their relative percentages). CI OCH3 H,CO CI CI CI Cle CH;CHCHCH,CH, + CH;CHCHCH,CH3 + CH,CHČHCH,CH, CH;OH CH;CH=CHCH,CH, 50% 35% 15%Na, NH3 H3C-C=C-CH3 CH3 H3C° Alkynes are reduced to trans alkenes by a process called dissolving metal reduction. The reaction uses sodium or lithium metal as the reducing agent and liquid ammonia as the solvent. The method is specific in the formation of trans alkenes from alkynes. The method involves two successive transfers of single electrons from the alkali metal to the triple bond, with abstraction of protons from the ammonia solvent. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions .CH3 H-NH2 CH3 :NH2 H3C H3CExplain the different products of the following two reactions by considering the mechanism by which each reaction proceeds. As part of your explanation, use the curved arrow formalism to draw a mechanism for each reaction. CH,OH CH2=CH-CH-CH, + Na*¯OCH, CH;=CH-CH-CH3 Br OCH, CH,=CH-CH-CH, + CH,OH – CH,=CH–CH–CH, + CH,CH=CHCH, Br OCH, OCH,