A solution was prepared by dissolving 1270 mg of K3 Fe (CN), (329.2 g/mol) in sufficient water to give 735 mL. Calculate a the molar analytical concentration of K3 Fe (CN)6. Molar analytical concentration = 5.2x10^-3 the molar concentration of K*. Molar concentration = 15.6x10^-3 3- the molar concentration of Fe (CN),. Molar concentration = 5.2x10^-3 Correct Correct b the weight/volume percentage of K3 Fe (CN),. Weight/volume percentage = 173 % (w/v) %3D the number of millimoles of K' in 63.0 mL of this solution. .983 mmol 3- ppm Fe (CN), * 1.73x10^3 ppm An error has been detected in your answer. Check for typos, miscalculations etc. before submitting your answer. Submit
A solution was prepared by dissolving 1270 mg of K3 Fe (CN), (329.2 g/mol) in sufficient water to give 735 mL. Calculate a the molar analytical concentration of K3 Fe (CN)6. Molar analytical concentration = 5.2x10^-3 the molar concentration of K*. Molar concentration = 15.6x10^-3 3- the molar concentration of Fe (CN),. Molar concentration = 5.2x10^-3 Correct Correct b the weight/volume percentage of K3 Fe (CN),. Weight/volume percentage = 173 % (w/v) %3D the number of millimoles of K' in 63.0 mL of this solution. .983 mmol 3- ppm Fe (CN), * 1.73x10^3 ppm An error has been detected in your answer. Check for typos, miscalculations etc. before submitting your answer. Submit
Chemistry by OpenStax (2015-05-04)
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ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
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Chapter4: Stoichiometry Of Chemical Reactions
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![A solution was prepared by dissolving 1270 mg of K3 Fe (CN), (329.2
g/mol) in sufficient water to give 735 mL. Calculate
a the molar analytical concentration of K3 Fe (CN)6.
Molar analytical concentration = 5.2x10^-3
the molar concentration of K*.
Molar concentration = 15.6x10^-3
3-
the molar concentration of Fe (CN),.
Molar concentration = 5.2x10^-3
Correct
Correct
b the weight/volume percentage of K3 Fe (CN),.
Weight/volume percentage = 173
% (w/v)
%3D
the number of millimoles of K' in 63.0 mL of this solution.
.983
mmol
3-
ppm Fe (CN),
*
1.73x10^3
ppm
An error has been detected in your answer. Check for typos,
miscalculations etc. before submitting your answer.
Submit](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3900af8f-4b3d-476d-abb3-430216d49dd5%2F4138045b-2bc1-4120-afa2-f6b13d7ff4c0%2Fmd9d7sh_processed.png&w=3840&q=75)
Transcribed Image Text:A solution was prepared by dissolving 1270 mg of K3 Fe (CN), (329.2
g/mol) in sufficient water to give 735 mL. Calculate
a the molar analytical concentration of K3 Fe (CN)6.
Molar analytical concentration = 5.2x10^-3
the molar concentration of K*.
Molar concentration = 15.6x10^-3
3-
the molar concentration of Fe (CN),.
Molar concentration = 5.2x10^-3
Correct
Correct
b the weight/volume percentage of K3 Fe (CN),.
Weight/volume percentage = 173
% (w/v)
%3D
the number of millimoles of K' in 63.0 mL of this solution.
.983
mmol
3-
ppm Fe (CN),
*
1.73x10^3
ppm
An error has been detected in your answer. Check for typos,
miscalculations etc. before submitting your answer.
Submit
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