C Programming please, need help. zy Section 3.16 - CIS 161: Introduction XAnswered: CODE C Given four values rAC□zy zyBooks - Build Co... V Vimm's Lair: Preser...74°FWindy✰ learn.zybooks.com/zybook/AVCCIS161McCarySummer2023/chapter/3/section/16Dashboard=zyBooks My library > CIS 161: Introduction to C Programming home > 3.16: Conditional expressionsExpectedCHALLENGE 3.16.2: Conditional expression: Print negative or positive.ACTIVITYCreate a conditional expression that evaluates to string "negative" if userval is less than 0, and "non-negative" otherwise. Ex: Ifuserval is -9, output is:Imported From Fire...-9 is negative.Replace the code comment /* Your solution goes here */ with your solution. The rest of the code, including theparentheses and semicolon, cannot be edited.+-2Learn how our autograder works480676.1279990.qx3zqy7671 #include 2 #include 384 int main(void) {5 char condStr[50];int userVal;9101112131415 }RunCHALLENGEscanf("%d", &userVal);strcpy(condStr, /* Your solution goes here */);printf("%d is %s.\n", userVal, condStr);return 0;8assignmentQ SearchOFeedback?1 testpassedAll testspassedFeedback?EzyBooks catalogHelp/FAQ• VPNLarry WilliamsX|||4:38 PM6/1/2023

Start the program.Declare the variables userVal as an integer to store the user input and condStr as…

CHALLENGE 3.16.2: Conditional expression: Print negative or positive. ACTIVITY Create a conditional expression that evaluates to string "negative" if userval is less than 0, and "non-negative" otherwise. Ex If userval is-9, output is: -9 is negative. Replace the code comment/* Your solution goes here */ with your solution. The rest of the code, including the parentheses and semicolon, cannot be edited. Learn how our autograder works 1 #include 2 #include 3 4 int main(void) { 5 6 7 8 9 10 11 12445 14 15) Run char condStr[50]; int userval; scanf("%d", &userval); strcpy(condStr, /* Your solution goes here */); printf("%d is %s.\n", userval, condStr); return 0; DID

CHALLENGE 3.16.2: Conditional expression: Print negative or positive. ACTIVITY Create a conditional expression that evaluates to string "negative" if userval is less than 0, and "non-negative" otherwise. Ex If userval is-9, output is: -9 is negative. Replace the code comment/* Your solution goes here / with your solution. The rest of the code, including the parentheses and semicolon, cannot be edited. Learn how our autograder works 1 #include 2 #include 3 4 int main(void) { 5 6 7 8 9 10 11 12445 14 15) Run char condStr[50]; int userval; scanf("%d", &userval); strcpy(condStr, / Your solution goes here */); printf("%d is %s.\n", userval, condStr); return 0; DID

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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C CodeApproved Libraries: <stdio.h><math.h><stdlib.h><time.h> (for srand(time(0)) only)
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