CH3 2. An unknown isomer of C4H9Cl has the ¹³C NMR and DEPT-135 spectra shown below: 13C NMR: 90 70 I 50 8 (ppm) CH3CH₂CH₂ CH₂CI A 30 I 1 10 DEPT-135: CH3 CH3-CHCH₂-CI B 90 70 I I 1 Circle the compound that is represented by these spectra. Clearly explain your reasoning. you will need to explain how each of the other three isomers was eliminated from consideration. 50 8 (ppm) C CH3CH₂ CH-CI CH3 30 I 10 CH3 CH3-C-CI CH3 I D

Organic Chemistry
9th Edition
ISBN:9781305080485
Author:John E. McMurry
Publisher:John E. McMurry
Chapter13: Structure Determination: Nuclear Magnetic Resonance Spectroscopy
Section13.SE: Something Extra
Problem 59GP: The mass spectrum and 13C NMR spectrum of a hydrocarbon are shown. Propose a structure for this...
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CH3
2. An unknown isomer of C4H9Cl has the ¹³C NMR and DEPT-135 spectra shown below:
13C NMR:
90
70
||||
A
50
8 (ppm)
CH3CH₂CH₂ CH₂ CI
30
10
DEPT-135:
CH3
CH3-CHCH₂-CI
B
90
70
Circle the compound that is represented by these spectra. Clearly explain your reasoning.
you will need to explain how each of the other three isomers was eliminated
from consideration.
50
8 (ppm)
CH3CH₂ CH-CI
CH3
C
30
10
CH3
CH3-C-CI
CH3
D
Transcribed Image Text:CH3 2. An unknown isomer of C4H9Cl has the ¹³C NMR and DEPT-135 spectra shown below: 13C NMR: 90 70 |||| A 50 8 (ppm) CH3CH₂CH₂ CH₂ CI 30 10 DEPT-135: CH3 CH3-CHCH₂-CI B 90 70 Circle the compound that is represented by these spectra. Clearly explain your reasoning. you will need to explain how each of the other three isomers was eliminated from consideration. 50 8 (ppm) CH3CH₂ CH-CI CH3 C 30 10 CH3 CH3-C-CI CH3 D
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