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- (9) The value of sec4 x tan³ x dx is. tan6 x A)- tan* x 4 6 + +C B) sec¹ x + TUTTERS 6* C secx + C C) Sectx_sex+CD) antx_ax+ 6 4Prove that: a) sin2(theta)/1+cos2(theta) = tan(theta) b) 1+sin2(theta)+cos2(theta)/1+sin2(theta)-cos2(theta) = cot(theta) c) sec8(theta)-1/sec4(theta)-1 = tan8(theta)/tan2(theta) d) cot(theta) cot(60-theta) cot(60+theta) = cot3(theta) e)cos5(theta) = 16cos5(theta)- 20cos3(theta)+5cos(theta) f) sin4(theta) = 4sin(theta) cos3(theta)-4cos(theta)sin3(theta)2 Cos II - (tan (_TT) = पा 6 3 prove