Calculate the standard enthalpy, AH°, in kJ/mol for the reaction below. C6H1206(s) + 9O2(g) → 6H2O(1) + 6CO2(g)

Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter9: Energy And Chemistry
Section: Chapter Questions
Problem 9.53PAE: 9.53 Using these reactions, find the standard enthalpy change for the formation of 1 mol of PhO(s)...
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Given the following data
C6H1206(s)
AHF°= -1274.5 kJ/moll
H20(1)
AHF°= -285.8 kJ/mol
CO2(g)
AHF°= -393.5 kJ/mol
Calculate the standard enthalpy, AH°, in kJ/mol for the reaction below.
C6H1206(s) + 9O2(g) → 6H20(1) + 6CO2(g)
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Transcribed Image Text:Given the following data C6H1206(s) AHF°= -1274.5 kJ/moll H20(1) AHF°= -285.8 kJ/mol CO2(g) AHF°= -393.5 kJ/mol Calculate the standard enthalpy, AH°, in kJ/mol for the reaction below. C6H1206(s) + 9O2(g) → 6H20(1) + 6CO2(g) Your Answer: Answer units
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