Calculate the position of the persons CoG when :Wb= the weight of the board (98N)?Fr= the reaction force exerted by the scales on the reaction board (570N) ?r = the distance between the pivot and the reaction force 1.900m ?b= the distance between the pivot and the CoG of the board (0.950 m) ?p= the distance between the pivot and then CoG of the person ? r- 1.74mb= the distance between the pivot and the CoG of the board=1.74/2=0.87p= distance between pivot and the CoG (Unknown = c of G)PivotTHte belbetween the pivot and the CoG of the personbPW₂VrF₁200>W₁ bFigure 4. Experimental layout for Centre of Gravity calculation using a Reaction Boardtechnique

Fr = 570 NWp = 880 NWb = 98 Nr = 1.74 mb = 0.87 m

Calculate the position of the persons CoG when : Wb= the weight of the board (98N)? Fr= the reaction force exerted by the scales on the reaction board (570N) ? r = the distance between the pivot and the reaction force 1.900m ? b= the distance between the pivot and the CoG of the board (0.950 m) ? p= the distance between the pivot and then CoG of the person ?

Calculate the position of the persons CoG when : Wb= the weight of the board (98N)? Fr= the reaction force exerted by the scales on the reaction board (570N) ? r = the distance between the pivot and the reaction force 1.900m ? b= the distance between the pivot and the CoG of the board (0.950 m) ? p= the distance between the pivot and then CoG of the person ?

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter12: Static Equilibrium And Elasticity

Section: Chapter Questions

Problem 8CQ: A body moving in a circle with a constant seed is in rotational equilibrium.

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