calculate the location of the centroid, the second moments and product of area for the cross-section if;D = 67 mm, B = 41 mm & t = 2.41 mmALTest beamAStrain gaugeW(a) Unsymmetrical cantilever beam with weight applied at the free endand at the "shear centre", so that there is no torsion induced.Section A-AStraingauge 1Straingauge 2bStrain gauge 3aB(b) Location of Huggenberger strain gaugesFrom these, calculate the orientation and position of neutral axis for pure bending in the vertical plane (i.e.bending about a horizontal axis).

The objective of this question is to calculate the location of the centroid, the second moments and…

Answered: calculate the location of the centroid,…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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12-39. The double-web girder is constructed from two plywood sheets that are secured to wood members at its top and bottom. If each fastener can support 3 kN in single shear, determine the required spacing s of the fasteners needed to support the loading P= is kN. Assume A is pinned and B is a raller. S0 mm Iso mm 250 mm -1.2 |50 mm s0 mm HIso mmF 12 mm 12 mm
1) The wavren truss loaded as shown is supported by a voller at C. Use the method of sections to compute the Force in bars hinge at G and by Вс, аnd CE. 800lb Goolb B F 20" A 20 20 20" 400lb 1000lb
2. Use the method of sections to determine the internal forces in members JI, DI, and DE. The structure is supported by a pin at A and a roller at G. L J 3 m K AN B H E F C D 2 -2 m--2 m2 m2 m2 m--2 m- 20 KN 30 kN 40 kN G
The rigid bar AD (figure STR-4) is supported by two steel wires of 1.5mm diameter (E = 200 GPa) and a pin and bracket at D. Knowing that the wires were initially taut. Determine the following: a. The additional tension in wire BE when a load P=900 N is applied at D. b. The additional stress in wire FC when a load P = 900 N is applied at D c. The corresponding deflection at point D.
Consider the truss structure and the loading given below. a) Compute the average axial stress on member AB, b) compute the average shear stress at the pin of connection A. d- 20 mm 600 mm 50 mm -S00 mm 60 kN 25 mm | I 20 mm 30 mm I20 mm 25 mm TOP VIEW OF MEMBER AB d = 30 mm
250 mm A D P = 25 kN B 30 60 C TOP VIEW 280 mm Member AD is fabricated by joining two bars (E0=205GP,, Ga=82GPA) and is pinned to plate ABC using a 5 mm diameter pins as shown in the figure. The yield strength of the pins is T,=890MPA. Plate ABC is a right triangle and is fixed along its edge BC. A 25KN Force P is then applied at end D causing a lateral strain in member AD with magnitude equal to 7.5x10-mm/mm. This also causes Point A to displace only along the horizontal resulting to a shear strain at point A equal to y,=+0.00165rad. Determine the following: 1. Poisson's ratio of material used in member AD, vAD 2. The normal strain in member AD, caD 3. The average stress experienced by pin A, T, 4. Factor of Safety of pin A with respect to yielding, FS,A 5. Displacement of point D, A,
GKN A ↑3m 3m Ay 3EN 5kN C K -3m 4KN HOLN hay GKN 3m 4KN H 3kN -3m. H KN -3m- 5kN DIGA Gy Solve the Ay and Gy of this unsymmetrical Howe Truss. After that, solve it using METHOD OF JOINTS. wb
Ana ly ze the sta tic a lly in d e term in a te b e am d is trib u tio n me th od. Draw shear and bending -moment diagram s. Sketch o f th e de fo rm e d structu re not needed. shown by the moment- 12 ft 28 ft w A B 3 lc 2 lc 3 lc -> 40 ft 20 ft 4 0 ft P(k) w (k/ft) 43.8 3.0
An assembly of bars are designed in Figure 1. The assembly is made of structural A-36 steel where bar AB and BC has a drameter of 50 mm. ASTM and 25 mm The respectively. determine дар between C and the rigid wall at D is initially 0-15 mm, the support reaction at A and D when the force P= 292 kN is applied at B 600mm 450mm 292- A B D
BADLY NEED IN 1HOUR PLS THANKYOU Above is a simple truss with P = 45.67 KN (write answers in kN in 2 decimals) Compute for the forces in: a. Member DA b. Member BH c. Member HI d. Member DG e. Member El f. Member AF g. Resultant Force Reaction of Support F (3 pts)
Determine the shear value when x = 6m (from the left) for the beam shown Where: P1 = 61kN; P2 = 42kN; W1 = 15kN/m; W2 = 24kN/m 4 m P1 P2 TITT w2 42 m² 4 R₂ R₁ 2m A CO EU 5 m W1 3 m E
250 mm A D P = 25 kN B 30 60 C TOP VIEW 280 mm Member AD is fabricated by joining two bars (E=205GPA, G,A=82GPA) and is pinned to plate ABC using a 5 mm diameter pins as shown in the figure. The yield strength of the pins is T,=890MPA. Plate ABC is a right triangle and is fixed along its edge BC. A 25KN Force P is then applied at end D causing a lateral strain in member AD with magnitude equal to 7.5x104mm/mm. This also causes Point A to displace only along the horizontal resulting to a shear strain at point A equal to y,=+0.00165rad. Determine the following: 1. Poisson's ratio of material used in member AD, vD 2. The normal strain in member AD, CAD 3. The average stress experienced by pin A, TA 4. Factor of Safety of pin A with respect to yielding, FS,A 5. Displacement of point D, A,

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