(c) O2(g) + 2MgF2(s) → 2MgO(s) + 2F2(g) = 140.76 J/K• mol s° (02g)) = 205.0 J/K•mol rxn S° (F2(g)) = 203.34 J/K · mol S° (MgO(s)) = 26.78 J/K · mol s° (MGF2(s)) = ? Enter your answer in the box provided. J/K · mol

Chemistry by OpenStax (2015-05-04)
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Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
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Chapter5: Thermochemistry
Section: Chapter Questions
Problem 31E: When a 0.740-g sample of trinitrotoluene (TNT), C7H5N2O6, is burned in a bomb calorimeter, the...
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Hello! I'm not sure for this question what do we do when one of the products are more than one mole and how does that affect the end calculation when I add the other product and reaction? 

(c) O2(g) + 2MgF2(s) → 2MgO(s) + 2F2(g)
AS"
= 140.76 J/K• mol
S (02(g)) = 205.0 J/K · mol
rxn
sº
S (F2(g)) = 203.34 J/K · mol
S (MgO(s)) = 26.78 J/K · mol
s" (MGF2(s)) = ?
Enter your answer in the box provided.
J/K · mol
Transcribed Image Text:(c) O2(g) + 2MgF2(s) → 2MgO(s) + 2F2(g) AS" = 140.76 J/K• mol S (02(g)) = 205.0 J/K · mol rxn sº S (F2(g)) = 203.34 J/K · mol S (MgO(s)) = 26.78 J/K · mol s" (MGF2(s)) = ? Enter your answer in the box provided. J/K · mol
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