C) Commercial Aspirin Tablet Analysis 1) Mass of aspirin used (g) 0.088g 2) Absorbance for final unknown solution (measured) 0.119 3) Molarity of final unknown solution (calculated from calibration curve) 2.085 x 10-4 mol/L 4) Molarity of original solution made from aspirin (in the 250.0 mL flask) 6.2 x 10-5 mol/L 5) Mass of ASA in original solution (g) 0.00280

C) Commercial Aspirin Tablet Analysis 1) Mass of aspirin used (g) 0.088g 2) Absorbance for final unknown solution (measured) 0.119 3) Molarity of final unknown solution (calculated from calibration curve) 2.085 x 10-4 mol/L 4) Molarity of original solution made from aspirin (in the 250.0 mL flask) 6.2 x 10-5 mol/L 5) Mass of ASA in original solution (g) 0.00280

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter7: Statistical Data Treatment And Evaluation

Section: Chapter Questions

Problem 7.10QAP

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The following data were collected for the reaction 2A + 2B + C 3G+ 4 F Experiment 2 3 4 5 [A] Units of Molarity .00125 .00250 .00125 .00125 .00301 [B] Units of Molarity 00125 .00125 00302 00302 .00100 [C] Units of Molarity 00125 .00125 .00125 00375 .00115 Rate Units M/s 00870 .0174 .0508 .457 a. What is the order with respect to each reactant and what is the overall order for the reaction? Answer this question within the answer box and show your work clearly labeled on the scratch paper. b. Write the rate law for the reaction. Answer this question within the answer box and show your work clearly labeled on the scratch paper. c. What is the value and units for k? Answer this question within the answer box and show your work clearly labeled on the scratch paper. d. Predict the rate for experiment 5, you should give a value and units. Answer this question in the answer box and show your work on the scratch paper labeled clearly.
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Section: Date: Solubility of Calcium Hydroxide in Water Concentration of standard HCl solution (M) Temperature of Ca(OH), solution (°C) Determination of a Solubility Product Constant 0.05 25 Report Table KSP.1: Titration Data (Calcium Hydroxide Solubility in Water) Trial 1 Oml Initial Buret Reading (mL) Final Buret Reading (mL) Volume of HCI Added (mL) 19.6ml 19.6m Sample Calculations [OH] from trial 1 (show calculations in box below) Concentration of Ca2+ (show calculations in box below) Value of Ksp (show calculations in box below) Molar solubility of Ca(OH)2 in water (show calculations in box below) Trial 2 19.6ml 35.2m) 15.6m)
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Average Volume of NaOH used: 16.3mL +16.3ml + 16.1ml + 16.3mL +16.1mL V. average = 16.22mL NaOHag) Uncertainty on average volume: 0.05+0.05 +0.05 + 0.05 + 0.05 AUerage = 0.05mL Final answer: 16.22 + 0.05mL Molar Concentration of HClag: Reaction Equation HCl(aq) - NaOH aq) - NaCl aq) – H2O() OH sa = 16. 22ml x - 1000ml
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we dissdve 350ml volumetric Flask.LWe call this sdlution (S) oa of hydrated cupric sulfate (cusoy.5H,0 in given.molar mass launol ). Cu:64 S-32 H+ 1 1. Write the equation of dirsociation of hydrated cupric sulfate in water. 12. Calculate the molar mass of hydrated cupric sulfate. 1.3. Determine the molar concentration of (S). 14. Deduce it's mass concentiation. 1.5.1ist te materials used. 16. Write the procedure of preparting (5).
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Sol. No. 1 2 3 4 5 Volume of KI (ml) 20 18 15 12 10 [KI] K 0.195121951 0.00039 0.175609756 0.0004 0.146341463 0.0005 0.117073171 0.0006 0.097560976 0.0004 Log K Q1) Plot Log K' on y-axis and Log [KI] on x-axis A) Slope = B) Intercept = e) Log K = D) K = Log [KI] -3.40894 -0.70969387 -3.39794 -0.75545136 -3.30103 -0.834632606 -3.22185 -0.931542619 -3.39794 -1.010723865