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Bromine is one of the few elements that is a liquid at room temperature. It vaporizes easily and has a beautiful red color in both the liquid and gaseous states. Bromine reacts readily with hydrogen gas to make hydrogen bromide. One way to represent this equilibrium is: 1/2 H2(g) + 1/2 Br2(g)2HBr(g) We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above. 1) 2 HBr(g) 2 H2(g) + Br2(g) K = 2) HBr(g) 2 1/2 H2(g) + 1/2 Br2(g) K2 = 3) H2(g) + Br2(g) 2 2HB1(g) K3 = Drag and drop your selection from the following list to complete the answer: 1/K (1/K)?

Bromine is one of the few elements that is a liquid at room temperature. It vaporizes easily and has a beautiful red color in both the liquid and gaseous states. Bromine reacts readily with hydrogen gas to make hydrogen bromide. One way to represent this equilibrium is: 1/2 H2(g) + 1/2 Br2(g)2HBr(g) We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above. 1) 2 HBr(g) 2 H2(g) + Br2(g) K = 2) HBr(g) 2 1/2 H2(g) + 1/2 Br2(g) K2 = 3) H2(g) + Br2(g) 2 2HB1(g) K3 = Drag and drop your selection from the following list to complete the answer: 1/K (1/K)?

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 51QRT: At room temperature, the equilibrium constant Kc for the reaction 2 NO(g) ⇌ N2(g) + O2(g) is 1.4 ×...
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Bromine is one of the few elements that is a liquid at room temperature. It vaporizes easily and has a beautiful red color in both the liquid and gaseous states. Bromine reacts readily with hydrogen gas to make hydrogen bromide. One way to represent this equilibrium is: 1/2 H2(g) + 1/2 Br2(g)HBr(g) We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above. 1) 2 HBr(g) 2 H2(g) + Br2(g) K1 = 2) HBr(g) |? 1/2 H2(g) + 1/2 Br2(g) K2 = 3) H2(g) + Br2(g) 2 2HB1(g) K3 = Drag and drop your selection from the following list to complete the answer: 1/K K2 (1/K)? Submit Answer Retry Entire Group No more group attempts remain
Transcribed Image Text:Bromine is one of the few elements that is a liquid at room temperature. It vaporizes easily and has a beautiful red color in both the liquid and gaseous states. Bromine reacts readily with hydrogen gas to make hydrogen bromide. One way to represent this equilibrium is: 1/2 H2(g) + 1/2 Br2(g)HBr(g) We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above. 1) 2 HBr(g) 2 H2(g) + Br2(g) K1 = 2) HBr(g) |? 1/2 H2(g) + 1/2 Br2(g) K2 = 3) H2(g) + Br2(g) 2 2HB1(g) K3 = Drag and drop your selection from the following list to complete the answer: 1/K K2 (1/K)? Submit Answer Retry Entire Group No more group attempts remain
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