Bromine and water react to form hydrogen bromide and oxygen, like this: 2 Br, (g) + 2 H,0(g) - 4 HBr(g) + 0,(g) Also, a chemist finds that at a certain temperature the equilibrium mixture of bromine, water, hydrogen bromide, and oxygen has the following composition: compound pressure at equilibrium Br, 49.2 atm H,0 80.9 atm HBr 94.3 atm O2 62.5 atm Calculate the value of the equilibrium constant K for this reaction. Round your answer to 2 significant digits. * = 0

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Chapter14: Chemical Equilibirum
Section: Chapter Questions
Problem 14.131QP: Molecular bromine, Br2, dissociates at elevated temperatures into bromine atoms, Br. Br2(g)2Br(g) A...
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Bromine and water react to form hydrogen bromide and oxygen, like this:
2 Br, (g) + 2 H,0(g) - 4 HBr(g) + 0,(g)
Also, a chemist finds that at a certain temperature the equilibrium mixture of bromine, water, hydrogen bromide, and oxygen has the following composition:
compound pressure at equilibrium
Br,
49.2 atm
H,0
80.9 atm
HBr
94.3 atm
O2
62.5 atm
Calculate the value of the equilibrium constant K for this reaction. Round your answer to 2 significant digits.
* = 0
Transcribed Image Text:Bromine and water react to form hydrogen bromide and oxygen, like this: 2 Br, (g) + 2 H,0(g) - 4 HBr(g) + 0,(g) Also, a chemist finds that at a certain temperature the equilibrium mixture of bromine, water, hydrogen bromide, and oxygen has the following composition: compound pressure at equilibrium Br, 49.2 atm H,0 80.9 atm HBr 94.3 atm O2 62.5 atm Calculate the value of the equilibrium constant K for this reaction. Round your answer to 2 significant digits. * = 0
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