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- PAGE NO. DATE : Two ratis separ Round exehange for CauCHo st in anate ewarter are aquees solutionoby?Give the solution with proper sig figs. 4.523 g O2 x ( 1 mol O2 / 32.00 g O2) x (– 533.7 kJ/ 3 mol O2) = – 25.14505313 kJ a. – 25.145 kJ b. – 25.14505313 kJ c. – 25 kJ d. – 25.1 kJ e. none of these f. – 25.15 kJ g. – 2 x 10^1 kJ h. – 3 x 10^1 kJ i. – 25.14 kJThe total amount Wunderhor Germany together and the us of enersy OF I mole (5. equal to a.) 18.01smol b.) the enthalpy of Formation C.) the themal comporents or the substanca d.) The tuctric enersy どりThe sum of the libvational erer)y, ro th tiohel ereisy, transitional elect onic enuray eversy ind mee wenery
- N Gve the structure of the mayor produc CrO, HSO HO- OH PCC 2. CH;Ch HBr, ROOR Ph AIC34.) Belapce euch ef the told SO.ce +rClkcapt a. Kz SOu lap)+ BaClzegs equations. bifels)t NaOHyag)+HC10ucag Nacio, cag) +H2O(1) > mg Ocss C. Mnes> d. Mg(s)+ MazOg(s) PO4 lag) +H20) + HzO)> HNOstag gi BaO,(s)+H,00) - >Bal(0H), laq) +Oz(gs 1. h. NH3l) + Ogl4)- NogsHow Hhe clectonic stouchue nd alcom indrak that thy the Seme p of It periedie table.