Book (BookID, Price, Year, Author, Subject) BorrowLog (BID, BookID, CustomerID, DateTime) Customer (CustomerID, CustomerName, Address, City) 1. Write the DML statement to add two data records for Book table Book. 2. Write the DML statement to change the price of the Book with ID=5 to 200 Book
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- Book (BookID, Price, Year, Author, Subject)
- BorrowLog (BID, BookID, CustomerID, DateTime)
- Customer (CustomerID, CustomerName, Address, City)
1. Write the DML statement to add two data records for Book table Book.
2. Write the DML statement to change the price of the Book with ID=5 to 200 Book
Step by step
Solved in 3 steps
- LAB - Select horses with logical operators The Horse table has the following columns: • ID integer, primary key • RegisteredName - variable-length string • Breed - variable-length string • Height-decimal number • BirthDate - date Write a SELECT statement to select the registered name, height, and birth date for only horses that have a height between 15.0 and 16.0 (inclusive) or have a birth date on or after January 1, 2020.he Horse table has the following columns: ID - integer, primary key RegisteredName - variable-length string Breed - variable-length string Height - decimal number BirthDate - date Write a SELECT statement to select the registered name, height, and birth date for only horses that have a height between 15.0 and 16.0 (inclusive) or have a birth date on or after January 1, 2020.The Movie table has the following columns: ID - integer, primary key Title - variable-length string Genre - variable-length string RatingCode - variable-length string Year - integer Write a SELECT statement to select the year and the total number of movies for that year. Hint: Use the COUNT() function and GROUP BY clause. NOTE: Starter code has been provided. Simply change the blanks ("_") to the appropriate entity/value.
- With the following table: PRODUCTS(PRODUCT_NUMBER, DESCRIPTION,PURCHASE_DATE,CATEGORY) Write the mySQL statement that will insert the following PRODUCT into the table: PRODUCT_NUMBER: ‘67832’ DESCRIPTION: ‘KRAZY CAT CEREAL’ PURCHASE_DATE: 2023-11-14 CATEGORY: ‘CPG’ Write the mySQL statement that will insert that product but without a description.You have been instructed to add a new student information to the students table. Because the student is new, he has no marks before, you should not add an amount to the CGPA. The Students table contains these columns: Student_id NUMBER(10) Student_name VARCHAR2(30) Student phone NUMBER(10) CGPA NUMBER(2,2) Which INSERT statements will accomplish your objective? O a. INSERT INTO students VALUES (365, 'Khalil',99554721, 0 ) O b. INSERT INTO students VALUES (365, 'Khalil',99554721, 'NO CGPA' ) O c. INSERT INTO students VALUES (365, 'Khalil',99554721, NULL ) O d. INSERT INTO students VALUES (365, 'Khalil',99554721) Which line of code has an error? 1. CREATE TABLE FRUITS VEGETABLES 2. FRUIT TYPE VARCHAR2, 3. FRUIT NAME CHAR (20), 4. QUANTITY NUMBER (4)); O a. 1 O b. 2 O c. 39. Write a SELECT statement that uses aggregate window functions to calculate the total due for all vendors and the total due for each vendor. Return 3 Columns: The vendor id from the Invoices table. The balance due (invoice_total-payment_total-credit_total) for each invoice in the invoices table with a balance greater than 0. The total balance due for all vendors in the Invoices table. Modify the column that contains the balance due for each vendor so it contains a cumulative total by balance due.
- 3. Write a SELECT statement that joins the Departments, Courses, and Instructors tables. This statement should return these columns: DepartmentName, CourseDescription, FirstName, and LastName. Use aliases for the tables and return only those courses with three units. Each course description should only be listed once. Sort the result set by DepartmentName and then by CourseDescription in ascending sequence.1) Write the SQL code that will create the table structure for a table named EMP. This table is a subset of the EMPLOYEE table. The basic EMP table structure is summarized in the table below. (Note that the EMP_NUM is the PK)? ATTRIBUTE(FIELD) NAME DATADECLARATION Constraints EMP_NUM INT Auto generated Identifier, start from 101 EMP_LNAME VARCHAR(15) Not null EMP_FNAME VARCHAR(15) Not Null EMP_INITIAL CHAR(1) EMP_HIREDATE DATE Default value is system date JOB_CODE CHAR(3) Make sure input is in the range500,501,502The ITEM table contains the following columns statement. Analyze the statement why it will fail during execution. ITEM ID NUMBER(9) VARCHAR2(20) NUMBER(5,2) VARCHAR2(10) NUMBER(5) SELECT NVL (100 / AMOUNT, “NONE") FROM ITEM; ITEM NAME BUY PRICE BRAND ID AMOUNT
- 7. Use the UNION operator to generate a result set consisting of three columns from the Products table: Discount status A calculated column that contains a value of DISCOUNTED or FULL PRICE Product_name The product_name column discount_percent The discount_percent column If the product has a discount_percent greater than 0, the Discount_status column should contain a value of DISCOUNTED. Otherwise, it should contain a value of FULL PRICE. Sort the final result set by product_name.The Horse table has the following columns: ID - integer, primary key RegisteredName - variable-length string Breed - variable-length string Height - decimal number BirthDate - date Write a SELECT statement to select the registered name, height, and birth date for only horses that have a height between 15.0 and 16.0 (inclusive) or have a birth date on or after January 1, 2020. -- Your SELECT statement goes hereSELECT *FROM HorseWHERE (Height >= '15.0' AND Height <= '16.0') OR BirthDate >= '2020-01-01';The Horse table has the following columns: ID - integer, auto increment, primary key RegisteredName - variable-length string Breed - variable-length string, must be one of the following: Egyptian Arab, Holsteiner, Quarter Horse, Paint, Saddlebred Height - decimal number, must be between 10.0 and 20.0 BirthDate - date, must be on or after Jan 1, 2015 Insert the following data into the Horse table: RegisteredName Breed Height BirthDate Babe Quarter Horse 15.3 2015-02-10 Independence Holsteiner 16.0 2017-03-13 Ellie Saddlebred 15.0 2016-12-22 NULL Egyptian Arab 14.9 2019-10-12 Notes: Your SQL code does not display any results in Develop mode. Use Submit mode to test your code. In another lab that creates the Horse table, RegisteredName is NOT NULL. In this l
