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Before the start of the PLC code including the functions below, the content of the memory byte MB8 was "1011'0100". If the content of the memory byte MBO is "1010'1010", and MB1 is "0001'1000", what will be the content of MB8 if input 10.0 is enabled? Hint: the INV function is a bit wise inversion function. %10.0 "TAG_IN" H H OR Byte INV Byte EN ENO EN ENO H %MBO %MB2 %MB2 "TAG VALUE1" IN1 OUT "TAG_RESULT "TAG RESULTIN %MB8 "TAG_RESULT %MB1 OUT-XNOR "TAG_VALUE2" IN2 O a. 1010'1010 O b. 1011'0100 ○ c. 0001'1000 ○ d. 0000'0001 Before the start of the PLC code including the functions below, the content of the memory byte MB8 was "1011'0100". If the content of the memory byte MBO is "1010'1010", and MB1 is "0001'1000", what will be the content of MB8 if input 10.0 is enabled? %10.0 "TAG_IN" OR Byte INV Byte EN ENO EN ENO H %MBO %MB2 "TAG VALUE1" IN1 OUT TAG RESULT %MB2 "TAG_RESULTIN %MB8 "TAG_RESULT OUT-XNOR" %MB1 "TAG_VALUE2" IN2 a. None of the choices O b. 1011'0100 ○ c. 1010'1010 O d. 1111'1110 O e. 0001'1000 Before the start of the PLC code including the functions below, the content of the memory byte MB8 was "1011'0100". If the content of the memory byte MBO is "1010'1010", and MB1 is "0001'1000", what will be the content of MB8 if input 10.0 is enabled? %10.0 "TAG_IN" OR Byte INV Byte EN ENO EN ΕΝΟ %MBO "TAG_VALUE1" %MB2 %MB2 %MB8 IN1 OUT "TAG RESULT "TAG RESULTIN "TAG_RESULT OUT-XNOR" %MB1 "TAG_VALUE2" IN2 Oa. None of the choices O b. 0001'1000 O c. 1011'0100 O d. 1010'1010 O e. 0000'0001

Before the start of the PLC code including the functions below, the content of the memory byte MB8 was "1011'0100". If the content of the memory byte MBO is "1010'1010", and MB1 is "0001'1000", what will be the content of MB8 if input 10.0 is enabled? Hint: the INV function is a bit wise inversion function. %10.0 "TAG_IN" H H OR Byte INV Byte EN ENO EN ENO H %MBO %MB2 %MB2 "TAG VALUE1" IN1 OUT "TAG_RESULT "TAG RESULTIN %MB8 "TAG_RESULT %MB1 OUT-XNOR "TAG_VALUE2" IN2 O a. 1010'1010 O b. 1011'0100 ○ c. 0001'1000 ○ d. 0000'0001 Before the start of the PLC code including the functions below, the content of the memory byte MB8 was "1011'0100". If the content of the memory byte MBO is "1010'1010", and MB1 is "0001'1000", what will be the content of MB8 if input 10.0 is enabled? %10.0 "TAG_IN" OR Byte INV Byte EN ENO EN ENO H %MBO %MB2 "TAG VALUE1" IN1 OUT TAG RESULT %MB2 "TAG_RESULTIN %MB8 "TAG_RESULT OUT-XNOR" %MB1 "TAG_VALUE2" IN2 a. None of the choices O b. 1011'0100 ○ c. 1010'1010 O d. 1111'1110 O e. 0001'1000 Before the start of the PLC code including the functions below, the content of the memory byte MB8 was "1011'0100". If the content of the memory byte MBO is "1010'1010", and MB1 is "0001'1000", what will be the content of MB8 if input 10.0 is enabled? %10.0 "TAG_IN" OR Byte INV Byte EN ENO EN ΕΝΟ %MBO "TAG_VALUE1" %MB2 %MB2 %MB8 IN1 OUT "TAG RESULT "TAG RESULTIN "TAG_RESULT OUT-XNOR" %MB1 "TAG_VALUE2" IN2 Oa. None of the choices O b. 0001'1000 O c. 1011'0100 O d. 1010'1010 O e. 0000'0001

Electric Motor Control
Electric Motor Control
10th Edition
ISBN:9781133702818
Author:Herman
Publisher:Herman
Chapter22: Sequence Control
Section: Chapter Questions
Problem 6SQ: Draw a symbol for a solid-state logic element AND.
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Before the start of the PLC code including the functions below, the content of the memory byte MB8 was "1011'0100". If the content of the memory byte MBO is "1010'1010", and MB1 is "0001'1000", what will be the content of MB8 if input 10.0 is enabled? Hint: the INV function is a bit wise inversion function. %10.0 "TAG_IN" H H OR Byte INV Byte EN ENO EN ENO H %MBO %MB2 %MB2 "TAG VALUE1" IN1 OUT "TAG_RESULT "TAG RESULTIN %MB8 "TAG_RESULT %MB1 OUT-XNOR "TAG_VALUE2" IN2 O a. 1010'1010 O b. 1011'0100 ○ c. 0001'1000 ○ d. 0000'0001 Before the start of the PLC code including the functions below, the content of the memory byte MB8 was "1011'0100". If the content of the memory byte MBO is "1010'1010", and MB1 is "0001'1000", what will be the content of MB8 if input 10.0 is enabled? %10.0 "TAG_IN" OR Byte INV Byte EN ENO EN ENO H %MBO %MB2 "TAG VALUE1" IN1 OUT TAG RESULT %MB2 "TAG_RESULTIN %MB8 "TAG_RESULT OUT-XNOR" %MB1 "TAG_VALUE2" IN2 a. None of the choices O b. 1011'0100 ○ c. 1010'1010 O d. 1111'1110 O e. 0001'1000 Before the start of the PLC code including the functions below, the content of the memory byte MB8 was "1011'0100". If the content of the memory byte MBO is "1010'1010", and MB1 is "0001'1000", what will be the content of MB8 if input 10.0 is enabled? %10.0 "TAG_IN" OR Byte INV Byte EN ENO EN ΕΝΟ %MBO "TAG_VALUE1" %MB2 %MB2 %MB8 IN1 OUT "TAG RESULT "TAG RESULTIN "TAG_RESULT OUT-XNOR" %MB1 "TAG_VALUE2" IN2 Oa. None of the choices O b. 0001'1000 O c. 1011'0100 O d. 1010'1010 O e. 0000'0001
Transcribed Image Text:Before the start of the PLC code including the functions below, the content of the memory byte MB8 was "1011'0100". If the content of the memory byte MBO is "1010'1010", and MB1 is "0001'1000", what will be the content of MB8 if input 10.0 is enabled? Hint: the INV function is a bit wise inversion function. %10.0 "TAG_IN" H H OR Byte INV Byte EN ENO EN ENO H %MBO %MB2 %MB2 "TAG VALUE1" IN1 OUT "TAG_RESULT "TAG RESULTIN %MB8 "TAG_RESULT %MB1 OUT-XNOR "TAG_VALUE2" IN2 O a. 1010'1010 O b. 1011'0100 ○ c. 0001'1000 ○ d. 0000'0001 Before the start of the PLC code including the functions below, the content of the memory byte MB8 was "1011'0100". If the content of the memory byte MBO is "1010'1010", and MB1 is "0001'1000", what will be the content of MB8 if input 10.0 is enabled? %10.0 "TAG_IN" OR Byte INV Byte EN ENO EN ENO H %MBO %MB2 "TAG VALUE1" IN1 OUT TAG RESULT %MB2 "TAG_RESULTIN %MB8 "TAG_RESULT OUT-XNOR" %MB1 "TAG_VALUE2" IN2 a. None of the choices O b. 1011'0100 ○ c. 1010'1010 O d. 1111'1110 O e. 0001'1000 Before the start of the PLC code including the functions below, the content of the memory byte MB8 was "1011'0100". If the content of the memory byte MBO is "1010'1010", and MB1 is "0001'1000", what will be the content of MB8 if input 10.0 is enabled? %10.0 "TAG_IN" OR Byte INV Byte EN ENO EN ΕΝΟ %MBO "TAG_VALUE1" %MB2 %MB2 %MB8 IN1 OUT "TAG RESULT "TAG RESULTIN "TAG_RESULT OUT-XNOR" %MB1 "TAG_VALUE2" IN2 Oa. None of the choices O b. 0001'1000 O c. 1011'0100 O d. 1010'1010 O e. 0000'0001
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