Based on the thermodynamic properties provided for water, determine the amount of energy needed for 2.20  kg of water to go from -14.0 °C to 74.0 °C.

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Chapter20: The First Law Of Thermodynamics
Section: Chapter Questions
Problem 20.12OQ: If a gas is compressed isothermally, which of the following statements is true? (a) Energy is...
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Based on the thermodynamic properties provided for water, determine the amount of energy needed for 2.20  kg of water to go from -14.0 °C to 74.0 °C. 
 

 

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Answer was incorrect, but i tried plugging in other values for Cp and they didn't work, is there another step to the problem

Chemistry: The Scie...
W Chemistry: The Sci...
< SW 10 chap 6 part b (fa22)
5th attempt
h G
Property
Melting point
Boiling point
AHfus
AHvap
Cp (s)
Cp (1)
Cp (8)
4th attemnt
W Smartwork5
kJ
4 OF 7 QUESTIONS COMPLETED
digital.wwnorton.com
Value
0.0
100.0
6.01
40.67
37.1
75.3
33.6
b Success Confirmati...
11/01/22 J
Chemistry: The Sci...
5
SCORE out of 9
Based on the thermodynamic properties provided for water, determine the amount of energy needed for 2.20 kg of water to go from
-14.0 °C to 74.0 °C.
Units
°℃
°C
kJ/mol
kJ/mol
J/mol • °C
J/mol • °C
J/mol • °C
Digital Resources fo...
< 01/07 >
Mail - Nyemah, Eliz...
.::See Periodic Table
elizabeth.nyemah@mnsu.edu
See Hint
kilograms to grams...
SUBMIT ANSWER
Transcribed Image Text:Chemistry: The Scie... W Chemistry: The Sci... < SW 10 chap 6 part b (fa22) 5th attempt h G Property Melting point Boiling point AHfus AHvap Cp (s) Cp (1) Cp (8) 4th attemnt W Smartwork5 kJ 4 OF 7 QUESTIONS COMPLETED digital.wwnorton.com Value 0.0 100.0 6.01 40.67 37.1 75.3 33.6 b Success Confirmati... 11/01/22 J Chemistry: The Sci... 5 SCORE out of 9 Based on the thermodynamic properties provided for water, determine the amount of energy needed for 2.20 kg of water to go from -14.0 °C to 74.0 °C. Units °℃ °C kJ/mol kJ/mol J/mol • °C J/mol • °C J/mol • °C Digital Resources fo... < 01/07 > Mail - Nyemah, Eliz... .::See Periodic Table elizabeth.nyemah@mnsu.edu See Hint kilograms to grams... SUBMIT ANSWER
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