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- Consider the following pedigree. 하 3 10 (5 3 2 (a) What pattern of transmission is most consistent with this pedigree? (1) autosomal recessive, (2) autosomal dominant, (3) X-linked recessive, (4) X-linked dominant. (b) If individual V-2 marries a normal individual, and if the condition has a pene-trance of 85 percent, what is the probability that their second child will express the trait? (c) On the third line, what does the diamond with a 10 in the middle mean?3. Short-tailed pup distribution. In mice, the dominant T allele results in a short tail. Homozygous T/T genotype is lethal, which means mouse embryos with this genotype die before they are born. Homozygous t/t is normal, with normal tail. A cross between two short-tailed mice produces a litter of 5 pups. a). What are the genotype(s) of the two short-tailed mice used in the cross? b). What are the possible genotypes and phenotypes of the 5 pups? What are their perspective ratio?Color blindness in humans is controlled by an X-linked completely recessive allele (Xc), while breast cancer is controlled by an autosomal completely dominant allele, B. A color blind male, who is a heterozygote carrier for breast cancer has three children/n with a normal eyed female (whose mother was color blind), who is homozygote recessive for the breast cancer allele. What is the probability that out of three children, 2 will be color blind males, and not show breast cancer, and one will be a color blind female, who shows breast cancer?
- Topic: Penetrance. Petal number is controlled by a single gene in merigonias. The gene has a completely dominant wild type allele F that makes a plant have five petals and a mutant recessive six petal allele(f). However the six petal trait is only 50% penetrant. You do the cross Ff x Ff. What fraction of the progeny do you have the 6 petals? what is the meaning for 50% penetrant.Incomplete Dominance 1. In snapdragons, red flower color (R) is incompletely dominant over white flower color (r). The hybrids or heterozygous plants (Rr) are pink in color. a) Show the genotype for a white flower and for a red flower. b) If a red-flowered plant is crossed with a white-flowered plant, what are the genotypes and phenotypes of the F1 generation plants? Show your work. c) What genotypes and phenotypes will be produced in the F2 generation? Show your work? the the o doa A t r th s beirs ard the phenorypic and wo ran aials pring fro d) How did the genotypic and phenotypic ratio compare to each other in this incomplete dominance cross? gonarypi and e) What would the phenotypic ratio have been if this had been complete dominance?You are a genetic counselor. How would you advise a couple who wants to know their chances of having a baby with Duchenne-muscular dystrophy. Hannah is not a carrier, but her husband Barry has a brother, James, who died from the disease. Duchenne-muscular dystrophy is an x-linked condition, the allele responsible is recessive and people who have the disease die in childhood. a)What are Hannah’s and Barry’s chances of having a baby with Duchenne-muscular dystrophy? b)What are the chances of Barry’s sister having a baby with the disease?
- X-linked Recessive Inheritance A gene is described as X-linked when it occurs on the X chromosome and not the Y. Our convention is to indicate X-linkage by attaching the appropriate gene symbol as a superscript on the letter X. Commonly, the wild-type (+) allele is indicated with only a "+" to avoid having to type a superscript on a superscript. For example, a female that is heterozygous and carrying a recessive mutant allele is indicated as X+Xm. Note the convenience of the shorthand + for m+ in this situation. A mutant male has the genotype XmY. When working with X-linked inheritance, always include the X and Y chromosomes in the descriptions of genotypes, and include the sex (male or female) in the descriptions of the phenotypes (e.g., mutant male, wild-type female, etc.). Here are the genotypes and associated phenotypes for X-linked recessive inheritance: X+X+ Wild-type female X+Xm Wild-type female xmxm Mutant female X+Y xmy Wild-type male Mutant maleA recessive epistasis cross gives in the F2 a 9:3:4 phenotypic ratio. What is the expected phenotypic ratio when the F1 (BbEe) is crossed with the double recessive homozygote (bbee)? Keeping in mind ee masks the expression of B.Pedigree 2: A. What is the most likely mode of inheritance of this disease? Choose from: autosomal dominant, autosomal recessive, X-linked dominant, X-linked recessive. B State the genotypes of individuals # 1 #4. C If individual #3 has another daughter with the same partner, what is the probability that this daughter will be affected (show the disease)?
- . Consider the imaginary trait, bristles with split-ends, a trait hypothesized to be X-linked dominant. In a cross, the P1 virgin females were homozygous wild type while the males had bristles with split-ends. The F1 84 males were all wild type while the 90 females all had split-ends. In addition, the data for the F2 generation revealed 26 wild type males, 35 wild type females, 29 split-end males and 40 split-end females. Is this what is to be expected? Use chi-square to prove your position.Homozygous mice are better able to adapt to their environment. O Heterozygous mice live shorter lives since they do not have the lethal allele. Is it possible to determine the genotype of an individual expressing a dominant phenotype? Provide evidence to support your claim * Provide at least 3 COMPLETE SENTENCES Your answer This is a required question Is it possible to determine the genotype of an individual expressing a recessive phenotype? Provide evidence to support your claim Provide at least 3 COMPLETE SENTENCES a phenotype is a personality's noticeable traits. Eye color, height and, evident. The genetic contribution to the constitution is named the genotype, So basically phenotypes are on the surfacel Yes it is possibleMiniature wings in Drosophila result from an X-linked allele (Xm) that is recessive to the allele for long wings (X+). Sepia eyes are produced by an autosomal allele (s) that is recessive to an allele for red eyes (s+). Q. A female fly that has miniature wings and sepia eyes is crossed with a male that has normal wings and is homozygous for red eyes. The F1 flies are intercrossed to produce the F2. Give the phenotypes, as well as their expected proportions, of the F1 and F2 flies.