(b) If such a circuit is to be used to supply an average of 10 V across the load, calculate the turns ratio of the transformer required. The input mains voltage is 240 V rms at 50 Hz. You may assume ideal diodes in your analysis. Note again that there is to be no smoothing of the load voltage.
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- Q5. For the following center tapped transformer, show the waveform across each half of the secondary winding and across Ri, when a 100 V peak sine wave is applied to the primarywinding. What is the PIV rating must the diode have? (Use constant voltage drop model for the Silicon diode) IN4001 Ry OV 10k) D IN4001For the circuit shown below, compute the maximum current through each resistor when terminal A is a) positive and, b) negative. Assume the diodes are ideal. (Will we convert to the RMS value to it's actual value?)3 Given the bridge-type full-wave rectifier circuit shown 220V 60Hz 220V:Es Es D1 D2 D3 D4 The load resistor is 220 and the transformer average current is 300mA. Determine: (a) Average value, RMS value, and frequency of load voltage VRL. (b) Average current and PIV of each diode. RL
- 1) How is the diode and zener diode in the electronic circuit and how they work?indicate the differences between them.2) Can a zener diode be used instead of a regular diode? please explain.3) Is it to step down and rectify the 220V AC signal by means of a transformer or to convert 220 V?rectify it and then reduce its value to the desired DC level using a voltage divider circuit?suitable.?4) Bridge type full wave rectification with two diodes full wave rectification using a medium ended transformerCompare the rectifier circuit and list its advantages and disadvantages relative to each other.5) What is the concept of PIV (Peak Inverse Voltage) for rectifier circuits?For which rectifier circuits is this value more important?ideal diodes are used in the circuit shown in figure . Sketch the output voltageIn a centre-tapped full wave rectifier, the diode having a forward resistance of 3 ohm and the load resistance equals to 750 ohm. The turns ratio of the centre tapped transformer is 20:1. The primary winding of transformer is fed from a supply voltage of 220 V (RMS) 50 Hz. Determine a) Average and RMS value of load currents b) DC voltage and DC power output c) AC input power d) ripple factor and e) rectifier efficiency.
- A full-wave rectifier uses 2 diodes. The internal resistance of each diode is 20 Q. The transformer RMS secondary voltage from centre tap to each end of the secondary is 50 V and the load resistance is 980 Q. Mean load current will be92) For three - phase half-wave Controlleed rectifier Shown in he figure: 1. Derive a fomu la for mean load Voltage. 2. praw the wave form of vo, i,,i, iy and voltage across thyristor 1 (r.) assuming highly inductive load and d = 120What is the zener diode and what are its advantages? In what region of their characteristic curve are zener diodes operated? At what value of zener current is the zener voltage normally specified? How does the zener impedance affect the voltage across the terminals of the device?
- In the circuit of the following figure, the input voltage Vs is 15 volts rms with a frequency of 60 Hz, R equals 150 Ohms and C equals 100,000 Pico Farads. The diodes are Germanium (Vd = 0.2 volts) and the Zener diode is 12 volts. a) The magnitude of the ripple voltage at Cb) The Magnitude of the Peak Inverse Voltage (PIV) for D1 and D2.1. An ideal single-phase source of 240 V, 60 Hz, supplies power to a load resistor of R = 100 2 via a single ideal diode. Determine: (a) The average and RMS values of load current. (b) The power dissipation. (c) The circuit power factor. (d) What must be the rating of the diode?A single-phase half wave uncontrolled rectifier circuit is operating with a purely inductive load and a source voltage of 100 sin (277t) V. An ideal PMMC ammeter is connected in series with the inductive load reads 20 A. Calculate the distortion factor of the rectifier. Answer Choices: a. 0.866 b. 0.707 c. 0.577 d. 0.816