At 298K, the equilibrium constant for the following reaction is 1.70x10-²: H₂SO3(aq) + H₂0 H30+ (aq) + HSO3(aq) The equilibrium constant for a second reaction is 6.40x10-8: HSO3(aq) + H₂0H30+ (aq) + SO3²- (aq) Use this information to determine the equilibrium constant for the reaction: H₂SO3(aq) + 2H₂02H30+ (aq) + SO3² (aq) K=

Introduction to General, Organic and Biochemistry
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Chapter7: Reaction Rates And Chemical Equilibrium
Section: Chapter Questions
Problem 7.32P: 7-32 A particular reaction has an equilibrium constant of 1.13 under one set of conditions and an...
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At 298K, the equilibrium constant for the following reaction is 1.70x10-²:
H₂SO3(aq) + H₂0 H30+ (aq) + HSO3(aq)
F3
The equilibrium constant for a second reaction is 6.40x10-8:
HSO3(aq) + H₂0 H30+ (aq) + SO3² (aq)
Use this information to determine the equilibrium constant for the reaction:
H₂SO3(aq) + 2H₂02H30+ (aq) + SO3² (aq)
K =
$
4
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000
000 F4
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Transcribed Image Text:At 298K, the equilibrium constant for the following reaction is 1.70x10-²: H₂SO3(aq) + H₂0 H30+ (aq) + HSO3(aq) F3 The equilibrium constant for a second reaction is 6.40x10-8: HSO3(aq) + H₂0 H30+ (aq) + SO3² (aq) Use this information to determine the equilibrium constant for the reaction: H₂SO3(aq) + 2H₂02H30+ (aq) + SO3² (aq) K = $ 4 Submit Answer 000 000 F4 R % [Review Topics] [References] Use the References to access important values if needed for this question. 5 T Retry Entire Group 9 more group attempts remaining Cengage Learning Cengage Technical Support FS <6 MacBook Air & 7 ◄◄◄ F7 Y U * 0 ►|| F8 ( 9 F9 -0 4 F10 ОР 4) Previous F11 + =
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