Assume a computer that has 16-bit integers. Show how each of the following values would be stored sequentially in memory in Little Endian order, assuming each address holds one byte sure to extend each value to the appropriate number of bits. Please just enter the value. a. 0x1AB2 b. OxA Blank # 1 Blank # 2 Blank # 3 A/
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- Memory address Data According to the memory view given below, if RO = Ox20008002 then LDRSB r1, [r0, #-4] is executed as a result of r1 = ?(data overlay big endian)? Øx20008002 ØXA1 Øx20008001 ØXB2 Øx20008000 Øx73 ØX20007FFE ØXD4 ØX20007FFE Lütfen birini seçin: O A. R1 = 0X7F O B. R1 = Oxffffffd4 O C. R1 = Oxffffff7F O D. R1=0XD4000000 O E. R1 = 0XD4Assume variables have logical addresses with 16-bit page numbers and 16-bit offset using the memory configuration below. (Note that each hexidecimal is 4 bits long and Ox means hexadecimal radix) Logical Address Format Page Table Physical Memory Physical Address (starting) Oxppppdddd Page Frame Frame Size (hex) Size (dec) Ox10000 Ox10000 2 Охс000 65536 PPpp: page number dddd: page offset 1 1 Оxd000 65536 3 2 Охе000 Ox10000 65536 3 Oxf000 Ox10000 65536 Translate the following addresses: What is the physical address for 0x00011119 What is the physical address for 0x00000001 What is the logical address for Oxd0000001 ? What is the logical address for Oxc0000002 ?Assume variables have logical addresses with 16-bit page numbers and 16-bit offset using the memory configuration below. (Note that each hexidecimal is 4 bits long and Ox means hexadecimal radix) Logical Address Format Physical Memory Physical Address (starting) Page Table Охрppdddd Page | Frame Frame Size (hex) Size (dec) 2 Охс000 Ox10000 65536 pppp: page number dddd: page offset 1 1 Оxd000 Ox10000 65536 3 2 Охе000 Ox10000 65536 3 Oxf000 Ox10000 65536 Translate the following addresses: What is the physical address for 0x0002ffff What is the physical address for Ox0000abcd ? What is the logical address for Oxf000000f ? What is the logical address for Oxc000bbcc ?
- The memory location at address of 0X003FB01 contains 1-byte memory variable J (0010_0001), and the memory location at the address of 0X003FB02 contains 1-byte memory variable K (0001 0010), see figure below. There is a 2-byte variable M which hold binary information M (1110 0101 0000 1i11). What is the address in hexadecimal format for 2-byte memory variable M, following little Endian computer? 7 Address in Data in Hex. Format Hex. Format 0X003FBF04 1110 0101 M OX003FBF03 0000 1111 0X003FBF02 0001 0010 0X003FBF01 0010 0001 J Its address in hexadecimal is 0X003FBF02. а. Its address in hexadecimal is 0×003FBF03. O b. Its address in hexadecimal is 0X003FBF04. Its address in hexadecimal is 0×003FBF01. d.Let's say that p is a pointer to memory and the next six bytes in memory (in hex) beginning at p's address are: aa bb cc dd ee ff. What value would be in x if the following code is run on a little- endian computer? uint16_t *q uint16_t x = (uint16_t *)p; q[0]; aa aabb bbaa aabbccdd ddccbbaaAssume variables have logical addresses with 16-bit page numbers and 16-bit offset using the memory configuration below. (Note that each hexidecimal is 4 bits long and Ox means hexadecimal radix) Logical Address Format Physical Memory Physical Address (starting) Page Table Oxppppdddd Page | Frame Frame Size (hex) Size (dec) Ox10000 Ox10000 2 Охс000 65536 pppp: page number dddd: page offset 1 1 Oxd000 65536 2 2 Oxe000 Ox10000 65536 3 Oxf000 Ox10000 65536 Translate the following addresses: What is the physical address for 0x0000ee00 ? What is the physical address for Ox00020001 ? What is the logical address for Oxe0001234 ? What is the logical address for Oxc0004268 ?
- The table below shows a segment of primary memory from a Von Neumann model computer Address Data 10101000 10001000 11001000 10011001 10100000 10101010 10110100 10111011 10001100 11001100 The program counter (PC) contains a value of 11001000. Find the value (in binary) that will be placed in MAR (memory address register)? MAR (in binray) %3D Find the value (in binary) that will be placed in MBR (memory buffer register)? MBR = (binray) %3DConsider the following table that represents part of the memory of a 16-bit address space that has an addressability of 2 bytes (like LC-3): ADDRESS OxFFFF OXOCOE OXOCOD Ox0C0C OXOCOB OXOCOA 0x0C09 0x0000 CONTENTS 1111 1111 1111 1111 1111 1110 1101 1100 0001 1011 1100 0101 0110 0101 1000 0111 1100 0000 0100 0000 0011 0001 0101 0010 0000 1100 0000 1101 0000 0000 0000 0000 The table above shows the addresses in hex (base 16) and the contents at the corresponding address in binary (base 2). A.) What are the contents in hex of the memory location at following address in binary: 0000 1100 0000 1110? (Enter hex like the following example: Ox2A3F)Consider the following image that represents part of the memory of a 16-bit address space that has an addressability of 2 bytes (like LC-3): A memory location can store an address. We call that memory location's contents a "pointer" since it's an address that "points" to another memory location. G.) Interpret the contents at address 0x0C0B as a pointer. (Enter hex like the following example: 0x2A3F) H.) What are the contents of the memory location that the pointer above is pointing to? (Enter hex like the following example: 0x2A3F) Another reference : LC-3 Opcodes in Hex ADD 0x1 JMP 0xC LDR 0x6
- Oeew s Sat DO D 4 Hene et e H P E Dei vi At D Metig eta O t TE Fie • REC In Net ASSIGNMENT 1. The table below presents a list of devices that are to be addressed in a certain memory space. They have been ordered in the manner in which S S they are to be addressed with the first component being placed on the upper end of memory, starting at address $000000. By considering the size each component, provide the start and end address using the appropriate hexadecimal value. l Device Description Device Name Amount of memory to address ROM Chip ROM 1 RAM 1 4KB RAM Chip 8KB ROM Chip ROM 2 4KB Peripheral PER 1 4 bytes Peripheral PER 2 2 bytes 2. Assume a very simple microprocessor with 12 address lines Let's assume we wish to implement all its memory space and we use 517x8 memory chigs. a. What is the size of the largest addressable memory? 1aa H Q O B CEOEAssume variables have logical addresses with 16-bit page numbers and 16-bit offset using the memory configuration below. (Note that each hexidecimal is 4 bits long and Ox means hexadecimal radix) Logical Address Format Physical Memory Physical Address (starting) Page Table Size (dec) 65536 65536 Frame Size (hex) Oxppppdddd Page Frame 2 Ox10000 Ox10000 Охс000 pppp: page number dddd: page offset 1 1 Oxd000 2 Охе000 Ox10000 65536 3 Oxf000 Ox10000 65536 Translate the following addresses: What is the physical address for 0x0002ffff ? What is the physical address for 0x0000abcd ?char S[1] = "1824"; allocated in address Ox100 If the machine uses little endian byte ordering which of the following table presents variable in machine memory Select one: a. Ox100 : 0x31 Ox001: 0x38 Ox102: 0x32 Ox103: 0x34 O b. Ox100 : 0x34 Ox001: 0x32 Ox102: 0x38 Ox103: 0x31