Assignment: In the figure, a force F, having a slope of 2 vertical to 3 horizontal, produces a clockwise moment of 330 ft-lb about A and a counterclockwise moment of 420 ft-lb about B. Compute the moment of F about C.
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A: We have given a figure Now by this figure, we have to calculate the moment F = 300N
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- Compute the combined moment of the two 50-lb forces about (a) point O and (b) point A. The moment is positive if counterclockwise, negative if clockwise. Assume a -7.8 in, b-3.4 in.F-50 lb. Answers: (a) Moi (b) MAI lb-in. lb-in.3' |Y 6' B X A force P passing through points A and B has a clockwise moment of 300 ft-lb about O. Compute the value of P. 5. In the figure above, a force P intersects the x-axis at 4 ft to the right of O. If its moment about A is 170 ft-lb counterclockwise and its moment about B is 40 ft-lb clockwise, determine its y- intercept.Compute the moment (positive if counterclockwise, negative if clockwise) of the 0.51-lb force about the pivot O of the wall-switch toggle. F = 0.51 1 Answer: Mo 10° 0.875" lb-in.
- A 366-N force is applied at A as shown. y = 370 mm. Determine (b) the smallest force applied at B that creates the same moment about D. Write numerical value and 2 decimal places. + for counterclockwise -100 mm- -200 mm y mm 25° A P D 125 mm C BDetermine the result ant R of the two forces applied to the bracket. Write R in terms of unit vectors along the r and y axes shown: gular plate Det 150 N the momente od anoo y' L--x 30% 200 N ba oni hag aluovio gi 35 q sq od edi onim ida ad doidw baroqraq ban lellen ibaag fs lollang 20o A and about point O.The block on a wmooth eclned plane n moving down with a corstant acceleration of 4 m/s m. The block on the inclined plane is 41 kg and the hanging mass is 24 kg The radius of the pulloy is 0.49 m The anglo theta is 31 degress Determine the moment of nerta of the putey 855 ROUND OFF FINAL ASWER UP TO 2 DECIMAL PLACES. INPUT THE NUMBER ONLY
- Replace the 30-kN force acting at point A by a force-couple system at (a) point O and (b) point B. At each point, give the magnitudes of the resultant force and moment. The moment is positive if counterclockwise and negative if clockwise. 30 kN 1. 26 3.6 m 7.5 m B Answers kN, Mo = kN-m (a) Point O: F= (b) Point B: F = kN. Mg = kN-m 26°C Partly sunny pe here to searchDetermine the moment of the force F about point O, about point A, and about the line OB. Find the general results in terms of F, a, b, and c. Then answer with these numbers: F = 320 N, a = 230 mm, b = 655 mm, c = 420 mm. FA 12-lb force P is applied to the control rod AB as shown. Knowing that the length of the rod is 5 in. and that a = 30°, determine the moment of the force about Point B by resolving the force into horizontal and vertical components in lb-in. Write the numerical value only and 2 decimal places. + for counterclockwise A Fa 65° P B 4
- Calculate the moment Mg of the 830-N force about the bolt at B. Simplify your work by first replacing the force by its equivalent force- couple system at A. The moment is positive if counterclockwise, negative if clockwise. Assume F = 830 N, r = 220 mm, h = 555 mm, 0 = 32% = 42° Answer: Mg = i 0 h F N.m1. Replace the two forces by a single equivalent force R and find the angle Ɵ between R andthe X-axis. 2. Calculate the moment of the 400N force about point O.A 444-N force is applied at A as shown. y = 207 mm. Determine (a) the moment of the 444-N force about D in N-m. Write numerical value and 2 decimal places. + for counterclockwise y mm. 25° P 100 mm- D 200 mm- 125 mm B