Assignment 2 Exercise 5 (HW 2): Let us assume the "Saw-Tooth" signal is having amplitude X. Check the Average & RMS values are same its magnitude. x(wt) X M 0 TT 2TT -X Wt
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A: It is given that:
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Q: IA VA + I V₁ ww R₁ + Consider the circuit above, where: Calculate: VA=6 V, R1-50, R2=8 0, R3=802 V₁…
A: Values are given as, VA=6 V, R1=5 Ω, R2=8 Ω, R3=8 Ω. Circuit diagram is given as,
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Q: check the numbers, E=21 VCE=7.8 and resistance colector 2.1 Kohms
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- The output voltage waveform of a four quadrant chopper is shown in figure. In the waveform, Vdc is input voltage, D is duty cycle ratio and T is cycle time. DT T. The RMS value of ripple component in output voltage is (A) Vác 2V VD-D (В) V(2D-1) (C) de de (D) V de VD- D? ydIn an experiment, the function generator is adjusted to generate a square voltage at a certain frequency. This voltage is displayed on an oscilloscope and the reading is 16 V peak-to-peak. The rms value of this voltage is .What will be the rms value of this voltage if the frequency is doubled? Select one: O 16 Vrms 32 Vrms O 8 Vrms . 8 Vrms ..... O 5.657 Vrms 5.657 Vrms ....... O 8 Vrms . 16 Vrms O 16 Vrms 8 Vrms ......For the below sinusoidal voltage trace displayed by the CRO, the time/cm switch is on 5ms/cm and the volt/cm switch is on 3 V/cm. a) the frequency will bel Hz b) the amplitude will be V.
- 2. For a sinusoidal voltage trace displayed by the CRO, the time/cm switch is on at 500µs/cm and volt/cm switch is on 5V/cm. The width of one complete cycle is 4cm and peak to peak height is 5cm. Find (a) the frequency, (b) peak to peak voltage, (c)the amplitude and (d) the rms valueA harmonic analysis of the current drawn by a CFL yields the following data. Find the rms value of current and the wwwwwwww total harmonic distortion (THD). Harmonics rms Current (A) 1357a 0.15 0.12 0.08 0.03 0.02In an experiment, the function generator is adjusted to generate a square voltage at a certain frequency. This voltage is displayed on an oscilloscope and the reading is 10 V peak-to-peak. The rms value of this voltage is .What will be the rms value of this voltage if the frequency is reduced to the half value? 3.536 Vrms . 3.536 Vrms O 5 Vrms . 1.7677 Vrms O 3.536 Vrms. 1.7677 Vrms O 5 Vrms . 5 Vrms ...... O 10 Vrms . 10 Vrms ......
- The sinusoidal voltage trace displayed by the CRO, the time/cm switch is on 50 µs/cm and the volt/cm switch is on 20 V/cm. The width of one complete cycle is 3.6 cm and the peak to peak height is 5.8 cm. Determine the following: The frequency is = The peak to peak voltage is = The amplitude is = The R.M.S voltage is =For the current waveform that shown in Figure below Find:- 1). Average value 2). R.M.S value 3). Form factor Current (A) ha 8 10 12 1-21) the RMS value of the current is? /2) the peak value of the voltage is?/3) the value of the reactive power is?
- -Consider the following DT sequence, Is this signal as Power Signal or Energy signal? Determine it. * 0Snくs X [n ]= lo-n 55.n510 • ther wise Power Signal, P=85 Energy Signal, E=85 O Neither energy nor Power O Both, P=30 E=55 -Is the following signal is X(4) - Sin 3t + Sin 大t Periodic AperiodicThe carrier frequency is 500 Hz, and the modulating signal is a single-tone sinusoidal signal. The x-axis is in time while the y- axis is the amplitude of the AM signal. Determine the peak voltage level of the modulating signal in V. 3 2 1 -1 -2 -3 -5 0.005 0.01 0.015 0.02 0.025 0.03 0.035 0.04 0.045 0.05 Time (s)A certain impedance is given by 1012° N. Does the current lead or lag the voltage, and by how many degrees? Fill in the blanks. The current the voltage by