Arrange the following FAs in decreasing melting point. * A. A 22-carbon series saturated FA B. An 18-carbon series saturated FA C. A 20-carbon series saturated FA D. A 20-carbon series monounsaturated trans- FA E. A 20-carbon series monounsaturated cis- FA F. A 20-carbon series polyunsaturated FA B-C-A-F-E-D O D-E-F-A-C-B O F-E-D-B-C-A O A-C-B-D-E-F
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- Part C The L isomer of H-C-OH H-C-OH H-C-OH О CHO О О О CH₂OH OH OH OH OH OH Submit OH ОН OH O OH OH O. OH OH OH O OH OH OH OH OH OH OH Request AnswerLefer to the figure showing the molecular structure of dimethylmercury. H–C-Hg C-H H. Exposure of human skin to a single drop of dimethylmercury can lead to death, as it is highly poisonous and passes easily cell membranes. Based on its structure, why is it able to pass so easily through cell membranes? I-0-I IICIHIn the space provided, draw a Haworth projection for the beta anomer of the following monosaccharide Fischer projection. CHO HO-C-H HO-C-H HO-C-H H-C-OH CH,OH
- The tripeptide abbreviated as Ala-Ser-Val is the same as the tripeptide abbreviated as Val- Ser-Ala. O True O FalseIdentify the chiral carbons in -D-fructose. Identify the appropriate atom by selecting an atom and assigning it a map number of 1. To do this, ri mark to enable the Map field before entering a value. EXP. CONT. но- S CI Br ÓH ÓH P F z OWhich of the following shorthand names best characterizes the following disaccharide? CHOH OH H. он H. H. OH Glc (a1-4)Gal Gal (a1-4)Glc O Glc (B1-4)Gal Gal (P1-4)Glc
- B-D-2-Deoxyribose is an aldopentose component of the nucleic acid structure with its -OH group at C-3 reduced to -H. O True O FalseDraw the step-by-step procedure of linear form (Fischer Projection) of a- D Glucose and B- D Glucose to Haworth. Paste the picture of your drawing below this image anomeric carbon H-č-OH HO-C-H H-C-OH H-C-OH anomers of glucose HO-C-H но-с—н H-C-OH H-Ċ-OH H-C-0- H-C-0- CH,OH CH,OH a-D-glucose B-D-glucoseDraw the step-by-step procedure of linear form (Fischer Projection) of a- D Glucose and B- D Glucose to Haworth. anomeric carbon H-C-OH HO-C-H H-C-OH H-Č-OH anomers of glucose HO-C-H но-с—н H Č-OH H-C-OH H-ċ-o H-C-0- CH,OH ČH,OH a-D-glucose В-D-glucose
- why does A2-B3 structure is active (contain the antibiotic) and the (A2- B2,A1-B1,A1-B2,A1-B3,A3-B1,A3-B2,A3- B3) are nonactive help please! atorial proce below. A1 A2 A3 N=0 H 2-nitrobenzaldehyde 5-nitro-2-furaldehyde 3-nitrobenzaldehyde B1 B2 NH₂ HN. 4-bromophenylhydrazine hydrochloride B3 NH₂ Br HN. 4-cyanophenylhydrazine hydrochloride NH₂ HN CẠNH NH₂ aminoguanidine bicarbonateA bi O=P-O-CH₂ 0- D Ribose sugar H H- B E N HH F OH H H. C NGN -H N H N HAla-Phe-Pro-Cys-Clu-Arg-Arg-Pro-His-Gly-Lys-Clu Calculate the net charge on the polypeptide at a. pH 1.5 b. pH 8 c. pH 13