An object of mass m is at rest at the top of a smooth slope of height h and length L. The coefficient of kinetic friction between the object and the surface, uk, V = - 4r VL? - h? is small enough that the object will slide down the slope if given a very small push to get it started. Submit Previous Answers v Correct Part B Sam, whose mass is 70 kg , stands at the top of a 14-m-high, 120-m-long snow-covered slope. His skis have a coefficient of kinetic friction on snow of 0.07. If he uses his poles to get started, then glides down, what is his speed at the bottom? Express your answer to two significant figures and include the appropriate units. • View Available Hint(s) HA m v = 10.48 S Submit Previous Answers

An object of mass m is at rest at the top of a smooth slope of height h and length L. The coefficient of kinetic friction between the object and the surface, uk, V = - 4r VL? - h? is small enough that the object will slide down the slope if given a very small push to get it started. Submit Previous Answers v Correct Part B Sam, whose mass is 70 kg , stands at the top of a 14-m-high, 120-m-long snow-covered slope. His skis have a coefficient of kinetic friction on snow of 0.07. If he uses his poles to get started, then glides down, what is his speed at the bottom? Express your answer to two significant figures and include the appropriate units. • View Available Hint(s) HA m v = 10.48 S Submit Previous Answers

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Q1
A box (m=7.02 kg) is placed on a horizontal surface with u=0.2. If a force of 5.9 N is pushing the box to the right but the box does not move. What is the magnitude of the static friction force ( in N) during the effect of the 5.9 N force? Select one: O A. 5.90 O B. 79.213 OC. 25 OD. 68.80 OE. 13.8 Next pag page
Mass 80 kg
1) Calculations for the red dog food can rolling down the slope in the Rube Goldberg design are as follows (we will name it Step 1): Step 1 (calculations are given): Coefficient of friction → μ = 0.14 Mass of the object-m-368 gm = 0.368kg Initial height of the object (red can on top of books) → h=8.89, cm = 0.0889 m Slope of the file folder → 9 = 14° Travelling Distance by the object = 11.5 inch = 0.292 m And length that the object will travel=h/sin 0 = 0.0889/ sin14° = 0.367 m So, the radius of the object →R=0.367 -0.292 = 0.075 m Initial Velocity of red can → u=0 Velocity and Force Calculations for Step 1: -From total mechanical energy conservation: → Initial mechanical energy = final mechanical energy → mg - In case of pure rolling, the velocity of the center of mass: →V=Ro= 0.075 x 14.28 = 1.07 m/s. -Hence the change in force acting on the object for the travel: →F=mgsin0 = 0.368 × 9.81 × sin14° =0.89 N Step 2: The Selective Step (Step 2) in this design and for the questions below…
1:E1 A docs.google.com/for Untitled Section Determine the force P required to lower the 40-kg cylinder at a slow steady speed. The coefficient or friction between the cord and its supporting surface is 0.30. (g-10 m/s³). 40 kg Your answer If (4, =0.4) then the o between the normal force N and the friction force F will be Your answer العربية الإنجليزية III
Hw.2 A (10 Kg mass) block is resting on a rough horizontal surface for which the coefficient of friction is (u-0.20). Determine the force Papplied to the block. EFx=0 5Pcos45-F=0 5P F=5Pcos45 45 EFy=0 N-5Psin45-98.1=D0 N=98.1+5Psin45 265 F=u N 5Pcos45=0.2*(98.1+5Psin45) P= F= N=
Question 2 A car, mass 1200kg, has its centre of gravity 900mm above the road. The track width is 1.6m and u between the tyres and road is 0.7. Determine: (a) the maximum speed at which the car will be able to negotiate a curve of 300m radius. (hint: check both conditions) (b) the maximum speed at which the car will be able to negotiate a banked track of 5° at a curve of 300m radius. (hint: check both conditions)
2. A 20 kg box sitting on a horizontal surface is pulled by a horizontal force of 64 N. The coefficient of kinetic friction between the box and the surface is 0.2. (Draw free-body diagram here) vsebn lognA en MOIT ANIMAX MATUM70038 blow 10 ode no tos 2010 Owl I 02 sa 0£to shingem seer sosot toriso 21 to obutingam and count onOno gol a. What is the normal force acting on the box?ib et bas 1910 marsib vbod-seil wai(1) b. What is the force of kinetic friction acting on the box? od no oond ton silt ei tad s c. What is the acceleration of the box? rss sdr to noitestsson sdt at tod in
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