An hemispherical structure made of lead (o = 5x10 6) isotropic and homogeneous is charge-free. The inner curved surface has radius a = 20 cm, and the thickness is 10 cm. Treating the problem as boundary-value problem, apply Laplace equation to derive: a) the resistance of the hemisphere, between its inner and outer curved surfaces; b) the capacitance of the hemisphere, between its inner and outer curved surfaces.

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An hemispherical structure made of lead (o = 5×10 ) isotropic and homogeneous is charge-free . The inner curved surface has radius a =
20 cm, and the thickness is 10 cm. Treating
the problem as boundary-value problem, apply Laplace equation to derive:
a) the resistance of the hemisphere, between its inner and outer curved surfaces;
b) the capacitance of the hemisphere, between its inner and outer curved surfaces.
Transcribed Image Text:An hemispherical structure made of lead (o = 5×10 ) isotropic and homogeneous is charge-free . The inner curved surface has radius a = 20 cm, and the thickness is 10 cm. Treating the problem as boundary-value problem, apply Laplace equation to derive: a) the resistance of the hemisphere, between its inner and outer curved surfaces; b) the capacitance of the hemisphere, between its inner and outer curved surfaces.
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