An arm ABC lying in a horizontal plane and supported at A (Figure 4) is made of two identical solid steel bars AB and BC welded together at a right angle. Each bar is 0.50 m long. Knowing that the maximum tensile stress (principal stress) at the top of the bar at support A due solely to the weights of the bars is 6.40 MPa, a) determine the diameter d of the bars. Density of steel is 7860 kg/m³. b) If bigger diameter or longer length of steel bars needed for the arm ABC, any modification can be made to support the same maximum tensile stress.

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter7: Analysis Of Stress And Strain
Section: Chapter Questions
Problem 7.2.26P: -26 A rectangular plate of dimensions 125 mm × 75 mm is subjected to tensile stress sy= 67 kPa and...
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An arm ABC lying in a horizontal plane and supported at A (Figure 4) is made of two
identical solid steel bars AB and BC welded together at a right angle. Each bar is 0.50 m
long. Knowing that the maximum tensile stress (principal stress) at the top of the bar at
support A due solely to the weights of the bars is 6.40 MPa,
a) determine the diameter d of the bars. Density of steel is 7860 kg/m³.
b) If bigger diameter or longer length of steel bars needed for the arm ABC, any
modification can be made to support the same maximum tensile stress.
B
Figure 4
Transcribed Image Text:An arm ABC lying in a horizontal plane and supported at A (Figure 4) is made of two identical solid steel bars AB and BC welded together at a right angle. Each bar is 0.50 m long. Knowing that the maximum tensile stress (principal stress) at the top of the bar at support A due solely to the weights of the bars is 6.40 MPa, a) determine the diameter d of the bars. Density of steel is 7860 kg/m³. b) If bigger diameter or longer length of steel bars needed for the arm ABC, any modification can be made to support the same maximum tensile stress. B Figure 4
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