An aqueous solution contains 0.213 M hydrosulfuric acid and 0.191 M hydrobromic acid. Calculate the sulfide ion concentration in this solution. [s?]=| mol/L. Acid Formula Kąl Ką2 Каз Acetic acid CH3COOH 1.8×10-5 Acetylsalicylic acid (aspirin) HC9H7O4 3.0×10-4 Aluminum ion Al(H2O)43+ 1.2×10-5 Arsenic acid НЗASO4 | 2.5x10-4 | 5.6×10-8 3.0×10-13 Ascorbic acid H2C6H6O6 |7.9×10-5 1.6×10-12 Benzoic acid СоHsCООн 6.3х105 Carbonic acid H2CO3 | 4.2×10-7 4.8×10-11 Ferric ion Fe(H2O)63+ 4.0x10-3 Formic acid НСООН 1.8×10-4 Hydrocyanic acid НCN 4.0×10-10 Hydrofluoric acid HF 7.2×10-4 Hydrogen peroxide H2O2 | 2.4x10-12 Hydrosulfuric acid H2S 1.0×10-7 1.0×10-19 Hypochlorous acid HC10 3.5×10-8 Nitrous acid HNO2 4.5x10-4 Oxalic acid H2C2O4 5.9×10-2 6.4×10-5 Phenol C6H5OH 1.0×10-10 Phosphoric acid НзРО4 7.5x10-3 6.2×10-8 | 3.6×10-13 Sulfuric acid H2SO4 very large 1.2×10-2 Sulfurous acid H2SO3 1.7×10-2 | 6.4×10-8 Zinc ion Zn(H2O)42+ 2.5×10-10
An aqueous solution contains 0.213 M hydrosulfuric acid and 0.191 M hydrobromic acid. Calculate the sulfide ion concentration in this solution. [s?]=| mol/L. Acid Formula Kąl Ką2 Каз Acetic acid CH3COOH 1.8×10-5 Acetylsalicylic acid (aspirin) HC9H7O4 3.0×10-4 Aluminum ion Al(H2O)43+ 1.2×10-5 Arsenic acid НЗASO4 | 2.5x10-4 | 5.6×10-8 3.0×10-13 Ascorbic acid H2C6H6O6 |7.9×10-5 1.6×10-12 Benzoic acid СоHsCООн 6.3х105 Carbonic acid H2CO3 | 4.2×10-7 4.8×10-11 Ferric ion Fe(H2O)63+ 4.0x10-3 Formic acid НСООН 1.8×10-4 Hydrocyanic acid НCN 4.0×10-10 Hydrofluoric acid HF 7.2×10-4 Hydrogen peroxide H2O2 | 2.4x10-12 Hydrosulfuric acid H2S 1.0×10-7 1.0×10-19 Hypochlorous acid HC10 3.5×10-8 Nitrous acid HNO2 4.5x10-4 Oxalic acid H2C2O4 5.9×10-2 6.4×10-5 Phenol C6H5OH 1.0×10-10 Phosphoric acid НзРО4 7.5x10-3 6.2×10-8 | 3.6×10-13 Sulfuric acid H2SO4 very large 1.2×10-2 Sulfurous acid H2SO3 1.7×10-2 | 6.4×10-8 Zinc ion Zn(H2O)42+ 2.5×10-10
Chapter16: Solubility And Complex Ion Equilibria
Section: Chapter Questions
Problem 111IP: Consider 1.0 L of an aqueous solution that contains 0.10 M sulfuric acid to which 0.30 mole of...
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