Ammonia gas can be prepared by the following reaction: CaO (s) + 2 NH4Cl(s) → 2 NH³ (g) + H₂O(g) + CaCl₂ (s) If 314 g of CaO and 628 g of NH4Cl are mixed, the theoretical yield of NH3 is 191 g. If only 133 g of NH3 is actually obtained, what is its percent yield? %

Chemistry for Engineering Students
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Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.24PAE: 4.24 Ammonia gas can be prepared by the reaction CaO(s)+2NH4Cl(s)2NH3(g)+H2O(g)+CaCl2(s) If 112 g of...
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Ammonia gas can be prepared by the following reaction:
CaO(s) + 2 NH4Cl(s) → 2 NH3 (g) + H₂O(g) + CaCl₂ (s)
If 314 g of CaO and 628 g of NH4Cl are mixed, the
theoretical yield of NH3 is 191 g. If only 133 g of NH3 is
actually obtained, what is its percent yield?
%
Transcribed Image Text:Ammonia gas can be prepared by the following reaction: CaO(s) + 2 NH4Cl(s) → 2 NH3 (g) + H₂O(g) + CaCl₂ (s) If 314 g of CaO and 628 g of NH4Cl are mixed, the theoretical yield of NH3 is 191 g. If only 133 g of NH3 is actually obtained, what is its percent yield? %
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