All crosses involve many more than one character. So far, only one character has been examined to help simplify the principles involved. Now, two pairs of alleles or two characters will be examined at the same time. In working the following problem, each pair of characteristics is on a different chromosome and will be inherited independently of the other (Principle of Independent Assortment). Problem 1: In garden peas, a homozygous recessive male plant with wrinkled, green seeds is crossed with a plant that is homozygous dominant for round, yellow seeds. Use this information to complete the following: Male phenotype= genotype= gametes= F2 phenotype= genotype= gametes= F, phenotype= F₁ genotype = Female Figure 12.10 Punnett Square for F₁ The F, genotype should be all RrYy. The gametes are formed from various combinations of these alleles. Each gamete must have one R and one Y. For example, the F, male gametes will be RY, Ry, rY, ry. Would the female gametes be the same as the male or different? Self-fertilize F, to obtain F₂. F2 phenotypic ratio=

All crosses involve many more than one character. So far, only one character has been examined to help simplify the principles involved. Now, two pairs of alleles or two characters will be examined at the same time. In working the following problem, each pair of characteristics is on a different chromosome and will be inherited independently of the other (Principle of Independent Assortment). Problem 1: In garden peas, a homozygous recessive male plant with wrinkled, green seeds is crossed with a plant that is homozygous dominant for round, yellow seeds. Use this information to complete the following: Male phenotype= genotype= gametes= F2 phenotype= genotype= gametes= F, phenotype= F₁ genotype = Female Figure 12.10 Punnett Square for F₁ The F, genotype should be all RrYy. The gametes are formed from various combinations of these alleles. Each gamete must have one R and one Y. For example, the F, male gametes will be RY, Ry, rY, ry. Would the female gametes be the same as the male or different? Self-fertilize F, to obtain F₂. F2 phenotypic ratio=

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Description: All crosses involve many more than one character. So far, only one character has been examined to helpsimplify the principles involved. Now, two pairs of alleles or two characters will be examined at the sametime. In working the following problem, e

Concepts of Biology

1st Edition

ISBN:9781938168116

Author:Samantha Fowler, Rebecca Roush, James Wise

Publisher:Samantha Fowler, Rebecca Roush, James Wise

Chapter8: Patterns Of Inheritance

Section: Chapter Questions

Problem 2ACQ: Figure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are...

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Three autosomal recessive mutations in yeast, all producing the same phenotype (m1, m2, and m3), are subjected to complementation analysis. Of the results shown below, which, if any, are alleles of one another? Predict the results of the cross that is not shown—that is, m2 * m3. Cross 1: m1 * m24 F1: all wild-type progeny Cross 2: m1 * m34 F1: all mutant progeny
type P = n! (p)* (q)"* х! (n - х)! Practice Problem: You cross a true-breeding pea plant with red flowers to a true-breeding pea plant with white flowers. All of your offspring have red flowers. Which gene is dominant? Why? What is the genotype of your offspring? You then cross the offspring to each other. What ratio do you expect? Why? You count 1000 plants and look at their flowers. Your results are as follows: 740 red 260 white Does this follow a simple Mendelian inheritance pattern? Why or why not? DADT 2 MEA SUDI ND D LUT IONS
Two pure-breeding lines of petunia plants are crossed. Line 1 plants grow to a height of 54 cm, and Line 2 plants grow to a height of 18 cm. Petunia plant height is controlled by three genes, A, B and C. Line 1 has the genotype A₁A₁B₁B₁C₁C₁, and line 2 has the genotype A2A2B₂B₂C₂C₂. Assume that genotype alone determines plant height under ideal growth conditions and that the alleles of the three genes are additive. If the F1 plants are self crossed, what is the expected proportion of F2 plants with the genotype A₁A₁B₁B₁C₁C₁ 1/8 1/32 1/16 1/4 1/64
Two plants in a cross were each heterozygous for two gene pairs (AB /ab) whose loci are linked and 30 map units (mu) apart. (Recall that 1 mu is equal to 1% recombination between two genes.) Assuming that crossing over occurs during the formation of both male and female gametes and that the A and B alleles are dominant, determine the phenotypic ratio of their offspring. Part E: What proportion of the offspring of two plants (both (AB/ab ) will be A - B- if the genes are 30 mu apart? Part F: What proportion of the offspring of two plants (both (AB/ab)) will be A - bb if the genes are 30 mu apart? Part G: What proportion of the offspring of two plants (both (AB/ab)) will be aaB- If the genes are 30 mu apart? Part H: What proportion of the offspring of two plants (both (AB/ab)) will be aabb if the genes are 30 mu apart?
Mendelian ratios are modified in crosses involving autotetraploids.Assume that one plant expresses the dominant trait greenseeds and is homozygous (WWWW). This plant is crossed to onewith white seeds that is also homozygous (wwww). If only onedominant allele is sufficient to produce green seeds, predict theF1 and F2 results of such a cross. Assume that synapsis betweenchromosome pairs is random during meiosis.
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A plant geneticist is examining the mode of inheritance of flower color in two closely related species of exotic plants. The first species may have two pure-breeding lines—one produces a distinct red flower; and the other produces flowers with no color at all, or very pale yellow flowers. However, she cannot be sure. A cross of these varieties produces all pink-flowered progeny. The second species exhibits similar pure-breeding varieties; that is, one variety produces red flowers; and the other produces an albino or very pale yellow flower. A cross of these two varieties, however, produces orange-flowered progeny exclusively. Analyze the mode of inheritance of flower color in these two plant species.
In'a Mendelian monohybrid cross, the F2 generation consists of 1/4 red-flowered, 1/2 pink-flowered, 1/4 white-flowered individuals. What does this indicate? For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). 14px A Ix BIUS Paragraph Arial ABC 田三 x² X2 田用因 Ť {} +]
In the common daisy, genes A and B control flower color. Both genes have a dominant allele (A or B) and a recessive allele (a or b). At least one copy of each dominant allele is required for flowers to be colorful instead of white. (Explain and Justify your answers) 21.1) Predict the genotypes and phenotypes of the F1 progeny of a cross between two white-flowered plants, one homozygous AA and the other homozygous BB. A) AA bb, white B) aa BB, white C) Aa Bb, colorful D) Aa Bb, white E) aa bb, colorful 21.2) Predict the phenotypic ratio of the F2 progeny of a cross between two white-flowered plants, one homozygous AA and the other homozygous BB. A) 3 colorful : 1 white B) 9 colorful : 7 white C) 9 white : 7 colorful D) 15 white : 1 colorful E) 15 colorful : 1 white 21.3) The inheritance pattern of daisy flower color provides an example of what type of gene interaction? A) additivity…
Lets consider two genes A and B linked at 5 CM. The recessive mutant alleles "a" and "b" are responsible for the mutant phenotypes [a] and [b] respectively. Two parents of pure strains but of unknown genotypes and phenotypes are crossed. The F1 is homogeneous with a [wild type] phenotype. The progeny of the test-cross on F1 individuals gives: 2.7% [a, b], 46.8% [a], 47.2% [b] and 3.3% [wild type]. This distribution shows that (tick the correct statements): genes A and B are dominant no correct answer the distance between A and B is about 6 cM genes A and B are linked the alleles are in cis position genes A and B are epistatic the distance between A and B is about 3 cM the distance between A and B is about 44 CM the alleles are in trans position genes A and B are independenta