(Algebra: solve 2 X 2 linear equations) You can use Cramer's rule to solve the following 2 x 2 system of linear equations: ed – bf af – ec y bc ax + by = e X = cx + dy = f ad ad – bc Write a function with the following header: void solveEquation(double a, double b, double c, double d, double e, double f, double& x, double& y, bool& isSolvable) If ad – bc is 0, the equation has no solution and isSolvable should be false. Write a program that prompts the user to enter a, b, c, d, e, and f and displays the result. If ad – bc is 0, report that "The equation has no solution." See Program- ming Exercise 3.3 for sample runs.

C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
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Chapter15: Recursion
Section: Chapter Questions
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(Algebra: solve 2 X 2 linear equations) You can use Cramer's rule to solve the
following 2 x 2 system of linear equations:
ed – bf
af – ec
y
bc
ax + by = e
X =
cx + dy = f
ad
ad – bc
Write a function with the following header:
void solveEquation(double a, double b, double c, double d,
double e, double f, double& x, double& y, bool& isSolvable)
If ad – bc is 0, the equation has no solution and isSolvable should be false.
Write a program that prompts the user to enter a, b, c, d, e, and f and displays the
result. If ad – bc is 0, report that "The equation has no solution." See Program-
ming Exercise 3.3 for sample runs.
Transcribed Image Text:(Algebra: solve 2 X 2 linear equations) You can use Cramer's rule to solve the following 2 x 2 system of linear equations: ed – bf af – ec y bc ax + by = e X = cx + dy = f ad ad – bc Write a function with the following header: void solveEquation(double a, double b, double c, double d, double e, double f, double& x, double& y, bool& isSolvable) If ad – bc is 0, the equation has no solution and isSolvable should be false. Write a program that prompts the user to enter a, b, c, d, e, and f and displays the result. If ad – bc is 0, report that "The equation has no solution." See Program- ming Exercise 3.3 for sample runs.
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