AH°1 = -76.6 kJ•mol AH°2 = -572 kJ•mol AH°3 = -348 kJ•mol- PQ-20. What is the enthalpy change for the N2Os(g) + H2O(1) → 2HNO;(1) 2H2(g) + O2(g) → 2H2O(1) N2(g) + 302(g) + H2(g) →2HNO3(1) reaction: %3D 2N2(g) + 502(g) 2N2O5(g) -> -977 kJ mol- (B) -543 kJ mol- 277 kJ mol- 29 kJ mol- (C) (D) (A)

Physical Chemistry
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ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Ball, David W. (david Warren), BAER, Tomas
Chapter2: The First Law Of Thermodynamics
Section: Chapter Questions
Problem 2.79E: The enthalpy of combustion of diamond is -395.4 kJ/mol. C s, dia O2 g CO2 g Determine the fH of C...
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AH°1 = -76.6 kJ•mol
AH°2 = -572 kJ•mol
AH°3 = -348 kJ•mol-
PQ-20. What is the enthalpy change for the N2Os(g) + H2O(1) → 2HNO;(1)
2H2(g) + O2(g) → 2H2O(1)
N2(g) + 302(g) + H2(g) →2HNO3(1)
reaction:
%3D
2N2(g) + 502(g) 2N2O5(g)
->
-977 kJ mol-
(B) -543 kJ mol-
277 kJ mol-
29 kJ mol-
(C)
(D)
(A)
Transcribed Image Text:AH°1 = -76.6 kJ•mol AH°2 = -572 kJ•mol AH°3 = -348 kJ•mol- PQ-20. What is the enthalpy change for the N2Os(g) + H2O(1) → 2HNO;(1) 2H2(g) + O2(g) → 2H2O(1) N2(g) + 302(g) + H2(g) →2HNO3(1) reaction: %3D 2N2(g) + 502(g) 2N2O5(g) -> -977 kJ mol- (B) -543 kJ mol- 277 kJ mol- 29 kJ mol- (C) (D) (A)
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