After testing the null hypothesis that the population difference = zero against an alternate hypothesis that the population means are different. Use a = 0.05 significance level. Paired Data, Accept or Reject Null hypothesis: Yes / No
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After testing the null hypothesis that the population difference = zero against an alternate hypothesis that the population
Paired Data, Accept or Reject Null hypothesis: Yes / No
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- Describe the standard normal distribution. What are its characteristics?Mean of nails in a store = 3/4 The mean of nail 1 = 3/4 ,st deviation, = 0.02 in The mean of nail 2 = 0.749 ,st dev = 0.0018 in The mean of nail 3 =0.751 ,st dev= 0.0015 in The manufacturer requires nails in the range 3/4 - 0.005 to 3/4 + 0.005. Which nail out of the 3 will be used which lies in the range with the highest probabiltyBut isn't the mean of the gamma distribution aplha (beta)
- LA random sample of size 50 is taken from a geometric distribution with a parameter 0.45. Find the variance of the sample mean. (X-bar)· A drug company is considering marketing a new local anesthetic. The effective time of the anesthetic the drug company is currently producing has a normal distribution with an average of 7.4 minutes with a standard devia- tion of 1.2 minutes. The chemistry of the new anesthetic is such that the effective time sho- uld be normal with the same standard devia- tion, but the mean effective time may be lo- wer. If it is lower, the drug company will market the new anesthetic; otherwise, they will continue to produce the older one. A sam- ple of size 36 results in a sample mean of 7.1. A hypothesis test will be done to help make the decision. Test hypothesis in level of significance = 0.10A special bumper was installed on selected vehicles in a large fleet. The dollar cost of body repairs was recorded for all vehicles that were involved in accidents over a 1-year period. Those with the special bumper are the test group and the other vehicles are the control group, shown below. Each "repair incident" is defined as an invoice (which might include more than one separate type of damage). Statistic Test Group Control Group Mean Damage x¯1x¯1 = $ 1,101 x¯2x¯2 = $ 1,766 Sample Standard Deviation s1 = $ 696 s2 = $ 838 Repair Incidents n1 = 12 n2 = 9 (a) Construct a 90 percent confidence interval for the true difference of the means assuming equal variances. (Round answers to 3 decimal places. Negative values should be indicated by a minus sign.) (b) Repeat part (a), using the assumption of unequal variances with Welch's formula for d.f. (Round answers to 2 decimal places. Negative values should be indicated by a minus sign.) (d) Construct separate…
- A special bumper was installed on selected vehicles in a large fleet. The dollar cost of body repairs was recorded for all vehicles that were involved in accidents over a 1-year period. Those with the special bumper are the test group and the other vehicles are the control group, shown below. Each "repair incident" is defined as an invoice (which might include more than one separate type of damage). Statistic Test Group Control Group Mean Damage X¯¯¯1X¯1 = $ 1,153 X¯¯¯2X¯2 = $ 1,751 Sample Std. Dev. s1 = $ 663 s2 = $ 820 Repair Incidents n1 = 16 n2 = 14 Source: Unpublished study by Thomas W. Lauer and Floyd G. Willoughby. (a) Construct a 99 percent confidence interval for the true difference of the means assuming equal variances. (Round your final answers to 3 decimal places. Negative values should be indicated by a minus sign.) The 99% confidence interval is from to (b) Repeat part (a), using the assumption of unequal variances with Welch's…A special bumper was installed on selected vehicles in a large fleet. The dollar cost of body repairs was recorded for all vehicles that were involved in accidents over a 1-year period. Those with the special bumper are the test group and the other vehicles are the control group, shown below. Each "repair incident" is defined as an invoice (which might include more than one separate type of damage). Statistic Test Group Control Group Mean Damage X¯¯¯1X¯1 = $ 1,077 X¯¯¯2X¯2 = $ 1,800 Sample Std. Dev. s1 = $ 693 s2 = $ 814 Repair Incidents n1 = 16 n2 = 13 Source: Unpublished study by Thomas W. Lauer and Floyd G. Willoughby. (a) Construct a 90 percent confidence interval for the true difference of the means assuming equal variances. (Round your final answers to 3 decimal places. Negative values should be indicated by a minus sign.) The 90% confidence interval is from to (b) Repeat part (a), using the assumption of unequal variances with Welch's…OLS estimator
- mg -) of 19 individuals are dL The serum cholesterol levels (in 225, 206, 201, 222, 232, 242, 249, 208, 198, 237, 254, 211, 230, 247, 218, 252, 240, 215, 213 Send data to calculator Send data to Excel Find 25th and 80" percentiles for these cholesterol levels. (If necessary, consult a list of formulas.) mg (a) The 25 percentile: dL mg (b) The 80th percentile: IPlever | Portal E Edulastic -> * app.edulastic.com/student/assessment/6047cfb343405200082ef515/class/S14b08b95dd16ded17187931/uta/60481 Question 7/8 > NEXT A BOOKMARK E7 The table below shows the frequency of FSA Writes essay scores for a particular group of students. Essay score Number of students 2. 3. 4. 4. 3. 2. 6. 1 How many students were in this data set? How many students earned at least a level 3 essay score? What ie the mode of the data cet? O Type here to search DELL F3 F4 F6 F7 FB F9 F10 Esc F2 4. 144 %23 %24 2 3 7 8 T. Y Tab Q F aps Lock C e in RThe Vitamin A levels in livers (μmol/L) between normal rats and radiation exposure rats are shown in the below table. Group Mean (μ) 35 25 Standard deviation (0) 2 3 Sample number (n) 50 Normal rats Radiation exposure rats (1) What is the standard error of mean (SEM) for each group? (2) Assume that the central-limit theorem is applicable. What does it mean in this context? 40