Add the following integers to an empty BST, print inorder, preorder, postorder sequences for the BST 7, 4, 6, 1, 2, 8, 3, 5 Inorder: All 7 Preorder: 8. 3 4 Postorder: 2 6
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- def strPattern(mystr):lenght = len(mystr)mystr1 = ""for i in range(lenght - 1):mystr1 = mystr1 + mystr[i].upper() + str(i + 1)if lenght == 0:return mystr1return mystr1 + mystr[-1].upper()s = input("enter a word: ")print(strPattern(s)) s = input("enter a word: ") EOFError: EOF when reading a line HOW CAN I FIX THIS QUESTION?IntSet unionWith(const IntSet& otherIntSet) const// Pre: size() + (otherIntSet.subtract(*this)).size() <= MAX_SIZE// Post: An IntSet representing the union of the invoking IntSet// and otherIntSet is returned.// Note: Equivalently (see postcondition of add), the IntSet// returned is one that initially is an exact copy of the// invoking IntSet but subsequently has all elements of// otherIntSet added.// IntSet intersect(const IntSet& otherIntSet) const// Pre: (none)// Post: An IntSet representing the intersection of the invoking// IntSet and otherIntSet is returned.// Note: Equivalently (see postcondition of remove), the IntSet// returned is one that initially is an exact copy of the// invoking IntSet but subsequently has all of its elements// that are not also elements of otherIntSet removed.// IntSet subtract(const IntSet& otherIntSet) const// Pre: (none)//…Python|you can use modules if necessary order is a list of pairs in the form of 'X-Y' order = ['A-C', 'A-D', 'A-H', 'A-S', '2-C', '2-D', '2-H', '2-S', '3-C', '3-D', '3-H', '3-S', '4-C', '4-D', '4-H', '4-S', '5-C', '5-D', '5-H', '5-S', '6-C', '6-D', '6-H', '6-S', '7-C', '7-D', '7-H', '7-S', '8-C', '8-D', '8-H', '8-S', '9-C', '9-D', '9-H', '9-S', '10-C', '10-D', '10-H', '10-S', 'J-C', 'J-D', 'J-H', 'J-S', 'Q-C', 'Q-D', 'Q-H', 'Q-S', 'K-C', 'K-D', 'K-H', 'K-S'] Notice that there are 13 X's and each of them is paired with 4 values of Y for better understanding please take reference here Y = ['C','D','H','S']X = ['A', '2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K'] 1.) I have a code that prints only the third and the first pair from the list above? Meaning it prints an X with the third and first Y in the list (order). However, It prints with a bracket[] and is separated with quotes ' '{see picture for my output} both needs to be removed. Also it only needs to print the first…
- # viewGame(G, i) takes a game description G (a dictionary of the type# produced by newGame()) and an integer player index i and returns a# string that, when printed, describes the state of the game from# player i's perspective.## Example:# >>> viewGame(G, 1)# '\nPlayer2 to play (score=0):\n 1[ ] 2[ ] 3[ ]'## Note the spacing and explicit newlines, and the fact that the player# numbers use 1-based indexing even though internally the game data# structures use Pythonic 0-based indexing.Write the implementations of functionscopy1 and copy2 for copying strings. copy1 uses array index notation. copy2 uses Pointers andPointer Arithmetic.#include <stdio.h>#define SIZE 10void copy1(char* s1, const char* s2); // prototypevoid copy2(char* s1, const char* s2); // prototypeint main(void){char string1[SIZE]; // create array string1char *string2 = "Hello"; // create a pointer to a stringcopy1(string1, string2);printf("string1 = %s\n", string1);char string3[SIZE]; // create array string3char string4[] = "Good Bye"; // create an array containing a stringcopy2(string3, string4);printf("string3 = %s\n", string3);}void copy1(char* s1, const char* s2){//Implement copying string using array index notation}void copy2(char* s1, const char* s2){//Implement copying string using Pointers and Pointer Arithmetic }Recamán's sequence def recaman_item(n):Compute and return the n:th term of the Recamán's sequence. See the linked definition for this sequence on Wolfram Mathworld. Note how the definition for the current element in this sequence depends on whether some particular number can be found in the previously generated prefix of the sequence. To allow your function to execute in a sure and speedy fashion even for millions of elements, you should use a set to keep track of which elements are already part of the prefix of the sequence generated so far. This way you can generate each element in constant time, instead of having to iterate through the entire previously generated list the way some "Shlemiel" might approach this problem. n Expected result 1 1 8 12 13 23 57 87 395743 258330 The previous version of this problem, simply called recaman in the very first versions of this problem collection,…
- IntSet unionWith(const IntSet& otherIntSet) const; //Unions the current set with the passed set. IntSet::unionWith(const IntSet& otherIntSet){ for (int i = 0; i < otherIntSet.used; ++i) //For each element in the passed set. { add(otherIntSet.data[i]); //Add it to current set. }}Find the error in each of the segments. If the error can be corrected, explain how ? short* numPtr, result;void* genericPtr{numPtr};result = *genericPtr + 7;Write a Python Code for the given function and conditions: Given function: def insert(self, newElement) Pre-condition: None. Post-condition: This method inserts newElement at the tail of the list. If an element with the same key as newElement already exists in the list, then it concludes the key already exists and does not insert the key.
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