Achondroplasia is a hereditary condition caused by a dominant allele in humans (dominant allele A). This disorder affects bone growth specifically in long bones of the upper and lower limbs by preventing the ossification of bones from cartilage. Determine the genotypes of the parents and offspring for the following family scenarios in a and b below. Two parents who have the Achondroplasia phenotype have 4 children where 1 is normal

Achondroplasia is a hereditary condition caused by a dominant allele in humans (dominant allele A). This disorder affects bone growth specifically in long bones of the upper and lower limbs by preventing the ossification of bones from cartilage. Determine the genotypes of the parents and offspring for the following family scenarios in a and b below. Two parents who have the Achondroplasia phenotype have 4 children where 1 is normal

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Description: Achondroplasia is a hereditary condition caused by a dominant allele in humans (dominant allele A). This disorder affects bone growth specifically in long bones of the upper and lower limbs by preventing the ossification of bones from cartilage. Dete

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter18: Genetics Of Behavior

Section: Chapter Questions

Problem 14QP: A pedigree analysis was performed on the family of a man with schizophrenia. Based on the known...

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Achondroplasia is a hereditary condition caused by a dominant allele in humans (dominant allele A). This disorder affects bone growth specifically in long bones of the upper and lower limbs by preventing the ossification of bones from cartilage. Determine the genotypes of the parents and offspring for the following family scenarios in a and b below. One parent with the Achondroplasia phenotype and a normal parent have 2 children. Both children have the Achondroplasia phenotype NOTE: You must draw a Punnet square to determine the possible genotypes of te children. When two alternative genotypes are possible for an individual, indicate both.
Duchenne muscular dystrophy is an inheritable disorder that results in muscle weakness, leading to walking and breathing difficulties and heart disease. Which of the following is a valid conclusion about the Duchenne muscular dystrophy pedigree shown above? a. Without further evidence, the genotypes of individuals II-2 and III-2 cannot be determined. b. Only individuals I-1 and II-3 are confirmed carriers of the Duchenne muscular dystrophy allele.
The following is a summary of the possible sickle-cell genotypes and phenotypes: AA - cojmpletely normal AS - sickle-cell trait (this person has a combination of normal hemoglobin and the abnormal, sickled form of hemoglobin) SS - sickle-cell anemia (all abnormal hemoglobin) If both parents and heterozygous for sickle-cell disease, what are the possible genotypes and phenotypes for their children?
Sickle cell anemia is inherited as an autosomal recessive condition. It also exhibits incomplete dominance in that the heterozygous genotype displays a mild form of the disease known as sickle cell trait while individuals with the homozygous recessive genotype have a severe form of SCA. A man who has severe sickle cell anemia marries a woman who suffers from a mild trait. What is the probabilitu they will have a child with severe SCA?What is the probability they will have a child with mild SCA? What is the probability they will have a normal child? Show ALL work using punnett squares.
The following is a summary of the possible sickle-cell genotypes and phenotypes: AA - cojmpletely normal AS - sickle-cell trait (this person has a combination of normal hemoglobin and the abnormal, sickled form of hemoglobin) SS - sickle-cell anemia (all abnormal hemoglobin) Fill in the punnett square and answer the question: If both parents and heterozygous for sickle-cell disease, what are the possible genotypes and phenotypes for their children?
The following is a summary of the possible sickle-cell genotypes and phenotypes: AA - cojmpletely normal AS - sickle-cell trait (this person has a combination of normal hemoglobin and the abnormal, sickled form of hemoglobin) SS - sickle-cell anemia (all abnormal hemoglobin) Make a punnett square for help answering the question: If both parents and heterozygous for sickle-cell disease, what are the possible genotypes and phenotypes for their children?
Cystic fibrosis in humans is caused by a recessive allele. A man is known to be a carrier of the cystic fibrosis allele. He marries a phenotypically normal woman. In the general population, the incidence of cystic fibrosis at birth is approximately 1 in 1,700. Assume Hardy-Weinberg proportions. What is the probability that the wife is also a carrier? Answer in decimal number only (three decimal places; example: 0.123). What is the probability that their first child will be affected? Answer in decimal number only (three decimal places; example: 0.123).
Niemann Pick Type C disease is a recessive disorder that causes the accumulation of cholesterol and other lipids in lysosomes, ultimately affecting both the liver and the nervous system. Below are the genotypes and phenotypes of offspring of a family with a history of Niemann Pick. 7 NN ( all normal phenotype) 3 Nn (all normal phenotype) 4 nn (1 early onset dementia, 1 mid-life onset dementia, 2 late-onset dementia). From this information, Niemann-Pick disease is an example of: A) variable expressivity B) incomplete dominance C) incomplete penetrance D) variable expressivity and incomplete penetrance E) multiple alleles
When phenylalanine is converted to phenylpyruvic acid, this molecule accumulates in the body and leads to a disorder known as phenylketonuria (PKU). PKU is due to the expression of a recessive allele,p. If both parents are heterozygous at the PKU locus, what is the probability of having first two affected children and then a normal child? Write the answer in the form 2!/1!1! *
Oculocutaneous Albinism is an inherited autosomal recessive condition caused by a mutation in the tyrosinase (TYR) gene. A male and female who are phenotypically normal, discover through genetic testing that they are both carriers of a TYR mutant allele. What is the probability that their first child will be biologically male and have Oculocutaneous Albinism? Select one: а. 1/8 b. 3/4 c. 1/4 d. 1/16 e. 1/2
A typical pedigree for a family that carries neurofibromatosis is shown below. Note that carriers are not indicated with half-colored shapes in this chart. Use the letter "N" to indicate the dominant neurofibromatosis allele, and the letter "n" for the normal allele. Use the below pedigree chart and your knowledge on how to interpret a pedigree chart to answer questions # 7-9. 1 Nn nn nn 3 nn 7. Is individual #1 most likely homozygous dominant or heterozygous? Explain how you can tell. 8. What is the genotype of individual #2? Explain how you can tell. 9. What is the genotype of individual #3? Explain how you can tell. 2)
Hemophilia is an X-linked disorder that affects the body’s ability to create blood clots. The allele for normal blood clotting, XH, is dominant over the allele for hemophilia, Xh. An unaffected female that is not a carrier mated with an affected male. Which of the following rows identifies the possible genotypes of the offspring? Select one: a. Female Male XHXH and XHXh XHY and XhY b. Female Male XHXh XHY c. Female Male XHXh XHY and XhY d. Female Male XHXH and XHXh XHY