a. Identify the following elements on the diagram. Aminoacyl site (A) Peptidyl site (P) Exit site (E) • Start codon Stop codon Amino end of the newly synthesized polypeptide chain Carboxyl end of the newly synthesized polypeptide chain Approximate location of the next peptide bond that will be formed b. Which release factor will bind to the ribosome when the stop codon is reached and in IL i4 bind?
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- 8. The following diagram illustrates a step in the process of translation. fMet Pro mRNA UAC GGG AUGCCCACG UAG a) Identify the following elements on the diagram. Aminoacyl site (A) Peptidyl site (P) Exit site (E) Amino end of the newly synthesized polypeptide chain Carboxyl end of the newly synthesized polypeptide chain Approximate location of the next peptide bond that will be formedWrite the sequence of the mRNA molecule synthesized from a DNA template strand having the sequence 5'-ATTACAGGCGGT-3' 5'- UAAUGUCCGCCA Incorrect Write the amino acid sequence encoded by the mRNA base sequence 5'-GAGUUAGUUUGUAAGUGC-3' Assume the reading frame starts at the 5' end. Refer to the codon table . Amino acid sequence: Glu-Leu-Val-Cys-Lys-Cys What is the sequence of the polypeptide formed on addition of poly(UUAC) to a cell-free protein-synthesizing system that does not require a start codon? Enter an amino acid sequence of four amino acids using the three-letter abbreviations. Polypeptide sequence: Poly( -3' Glu-Leu-Val-Cys-Lys-CysThe following segment of DNA in a hypothetical model organism encodes a polypeptide containingSEVEN amino acids. Pretend this short polypeptide is a completely functional enzyme. DNA tripletsencoding the translation initiation (or start) codon and a stop codon are included in the sequence.3 •GGGTACGATCGGAAAGTTGGTTCICCGGTATAGCTG5'5•CCCATGCTAGCCTTTCAACAAAGAGGCCATATCGAC.3'a. Label which of the DNA strands is the template strand and which is coding strand. b. Below, show sequence and the polarity of the mRNA encoded by this 'gene'. Determine theamino acid sequence of the polypeptide (use three letter codes for the amino acids) andidentify the N- and C- terminal ends of the polypeptide. please help. I am confused. c. Which of the 7 side chains in this polypeptide can form hydrogen bonds with polar molecules(like water)? Place a circle around these.d. Some amino acids on a polypeptide can be modified post-translationally. Thesemodifications may have some effect on the function of the…
- Given the following codons and their corresponding amino acids: UUU-Phenylalanine GAA- Glutamate CAA- Glutamine AAU- Asparagine AAC- Asn AAA- Lysine UCU- Serine GGA-Glycine ACC-Threonine AUG- Met/ START codon CCU- Proline GUU- Valine UAU-Tyrosine UAA- STOP AGG- Arginine AUU- Isoleucine CAU- Histidine GCU- Alanine UGU-Cysteir GAU-Asparti CUA-Leucine UGG-Tryptol CGU-Arginin Box 1: Show the mRNA sequence which codes for the short peptide, lys-ala-phe- leu. Include what should come before and after this short message. Don't leave any spaces between the letters. Box 2: Show the tRNA anticodon sequence that would line up with the mRNA strand from Box 1. Don't leave any spaces between the letters. Box 3 & 4: Show the DNA base sequence that would be found in the DNA double helix which carries the gene for this peptide. Give the coding strand sequence in Box 3 and template strand sequence in Box 4. Don't leave any spaces between the letters. Box 5: What if there was a frameshift at leucine…An RNA polymer is made by using the enzyme polynucleotide phosphorylase with equal quantities of CTP and GTP. When this RNA is used in an in vitro translation system, all of the following amino acids could be incorporated into a newly made polypeptide, except: Codon Table Second position C UUU UCU UAU UGU phe tyr сys UUC UCC UAC UGC ser UAA Stop UGA Stop UAG Stop UGG trp UUA UCA UUG UCG CUU CCU CAU CGU leu his ССС pro ССА CỤC САС CGC arg CỦA САА CGA gln CUG CCG CAG CGG AUU ACU AAU AGU asn ser AUC ile ACC thr АCА AAC AGC AUA AAA lys AAG AGA arg AUG met ACG AGG GUU GCU GAU GGU asp GUC GCC ala GCA GẠC GGC val gly GUA GAA GGA glu GUG GCG GAG GGG glycine (Gly) histidine (His) proline (pro) alanine (Ala) arginine (Arg) Third position (3'-end) AGUCAG First position (5'-end)What polypeptides would be formed from the sequence UCAATGGGGUUUAUAGCG… (there are bases after the last G but we don’t know what they are so there may be some ambiguity for the last codon with regards to the amino acid possibilities) if the translation frame had UCA as the first codon: if the translation frame had CAA as the first codon: if the translation frame had AAT as the first codon:
- 1. Considering the following nucleotide sequence in an mRNA molecule: 5’ AUG UUA CGU AAU GCU GUC GAA UCU AUU UGC UUU ACA UAA 3' a) Write the sequence of the DNA template (antisense) strand from which the mRNA was synthesized. b) Write the sequence of the DNA coding (sense or informational) strand complementary to the template strand. c) Write the sequence of tRNA anticodon that corresponds to the given mRNA molecule. d) Write the amino acid sequence of the peptide synthesized from the given mRNA nucleotide sequence. e) Draw the structure of the pertide fragment made up of the first five (5) amino acids in the given polypeptide.An RNA polymer is made by using the enzyme polynucleotide phosphorylase with equal quantities of CTP and GTP. When this RNA is used in an in vitro translation system, all of the following amino acids could be incorporated into a newly made polypeptide, except: Codon Table Second position A G UUU UCU UAU UGU phe tyr сys UUC UCC UAC UGC ser UAA Stop UGA Stop A UAG Stop UGG trp UUA UCA UUG UCG CUU CCU CAU CGU leu ССС pro his CAC CUC CGC arg CỦA ССА CAA CGA gln CUG CCG CAG CGG AUU ACU AAU AGU asi se ACC thr ACA AUC ile AAC AGC AUA AAA lys AAG AGA arg AUG met ACG AGG GUU GCU GAU GGU asp GGC gly GGA GUC GCC ala GCA GAC val GUA GAA glu GAG GUG GCG GGG proline (pro) histidine (His) O arginine (Arg) alanine (Ala) glycine (Gly) Third position (3'-end) First position (5'-end)Draw a schematic of translation. Include the following: • 5'and 3'of MRNA nucleic acid • N and C of peptide A, P, E sites • The mRNA should be AUGCACUACAUU • There should be a peptide bond formed between the first two amino acids but that's it. Codons Found in Messenger RNA Second Base U A G Phe Ser Тyr Tyr Stop Stop Phe U Leu Ser Cys Ser Leu Ser Trp Leu Pro His Arg Arg Arg Arg Leu Pro His Leu Pro Gln Leu Pro Gln lle Thr Asn Ser A lle Thr Asn Ser lle Thr Lys Arg Met Thr Lys Arg Asp Gly Gly Gly Gly Val Ala Val Ala Asp G Val Ala Glu Val Ala Glu Third Base UCAG UCAG UCAG UCAG First Base
- UCAAUGGGGUUUAUAGCG… (there are bases after the last G but we don’t know what they are so there may be some ambiguity for the last codon with regards to the amino acid possibilities) if the translation frame had UCA as the first codon: if the translation frame had CAA as the first codon: if the translation frame had AAT as the first codon:Refer to the codon diagram on. Which of the following is a codon that will terminate translation?* ates es Ders rences anline Gly (G) Leu (F) Ser (S) Ty 3. Asp (E) (D) C la Ala (A) GU Cys (C) eriods 1 and 2 G ds P1, Highschool pol MP3, P4 Trp (W) AC Arg (R) Leu (L) Ser (S) Lys (K) C. Pro Asn (N) (P) His The (H) Thu Fri Gin (0) INTLUsing the given information, determine the correct order of the following events during translation: TRNA-methionine is cleaved and moves the empty tRNA to E site & is released, TRNA with polypeptide chain moves to P site. Second tRNA binds to 1. Step 1 codon in A site 2. Step 2 Ribosome arrives at stop codon & polypeptide chain is released from TRNA 3. Step 3 4. Step 4 A peptide bond is created between the first amino acid and the second amino 5. Step 5 acid. 6. Step 6 TRNA-methionine binds to the start codon and the large ribosomal unit binds Small subunit scans MRNA until it reaches start codon