À well-known brokerage firm executive claimed that 90% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 100 people, 94% of them said they are confident of meeting their goals. Test the claim that the proportion of people who are confident is larger than 90% at the 0.005 significance level. The null and alternative hypothesis would be: Ho:p > 0.9 Ho:µ < 0.9 Ho:e > 0.9 Ho:p< 0.9 Họ:p=0.9 Họ:µ = 0.9

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section: Chapter Questions
Problem 8CR
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A well known brokerage firm executive claimed that 90% of investors are currently confident of meeting their investment goals.
A well-known brokerage firm executive claimed that 90% of investors are currently confident of meeting their
investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample
of 100 people, 94% of them said they are confident of meeting their goals.
Test the claim that the proportion of people who are confident is larger than 90% at the 0.005 significance
level.
The null and alternative hypothesis would be:
Họ:p > 0.9 Họ: fe < 0.9 Ho:µ > 0.9 Ho:p< 0.9 Họ:p=0.9 Họ: µ = 0.9
H1:p < 0.9 H1:H> 0.9 H1:µu < 0.9 H1:p > 0.9 H1:p # 0.9 H1:µ#0.9
The test is:
left-tailed right-tailed two-tailed
The test statistic is:
(to 3 decimals)
The p-value is:
(to 4 decimals)
Transcribed Image Text:A well-known brokerage firm executive claimed that 90% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 100 people, 94% of them said they are confident of meeting their goals. Test the claim that the proportion of people who are confident is larger than 90% at the 0.005 significance level. The null and alternative hypothesis would be: Họ:p > 0.9 Họ: fe < 0.9 Ho:µ > 0.9 Ho:p< 0.9 Họ:p=0.9 Họ: µ = 0.9 H1:p < 0.9 H1:H> 0.9 H1:µu < 0.9 H1:p > 0.9 H1:p # 0.9 H1:µ#0.9 The test is: left-tailed right-tailed two-tailed The test statistic is: (to 3 decimals) The p-value is: (to 4 decimals)
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