A voltage waveform e(t) is described as follows, for the first half-cycle: e(t) = 60 volts at t = 0 sec., Increases linearly to 100 volts at t=0.005 sec., Decreases linearly to 60 volts at t=0.01 sec. Determine the root-mean-square or RMS value of this voltage, noting that, at least for a half- cycle, the RMS procedure involves squaring the voltage, taking the mean of the square, and taking the square root of the mean.

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.1MCQ: The rms value of v(t)=Vmaxcos(t+) is given by a. Vmax b. Vmax/2 c. 2Vmax d. 2Vmax
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4. A voltage waveform e(t) is described as follows, for the first half-cycle:
e(t) = 60 volts at t = 0 sec.,
%3!
Increases linearly to 100 volts at t=0.005 sec.,
Decreases linearly to 60 volts at t=0.01 sec.
Determine the root-mean-square or RMS value of this voltage, noting that, at least for a half-
cycle, the RMS procedure involves squaring the voltage, taking the mean of the square, and
taking the square root of the mean.
Transcribed Image Text:4. A voltage waveform e(t) is described as follows, for the first half-cycle: e(t) = 60 volts at t = 0 sec., %3! Increases linearly to 100 volts at t=0.005 sec., Decreases linearly to 60 volts at t=0.01 sec. Determine the root-mean-square or RMS value of this voltage, noting that, at least for a half- cycle, the RMS procedure involves squaring the voltage, taking the mean of the square, and taking the square root of the mean.
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