A velocity field with no components in the y and zdirection is given by:V = 6 + 2xy + t2.The acceleration along the x-direction at a point(3, 1, 2), at time 2, is:(a) 8 units(b) 16 units(c) 28 units(d) 36 units

Answered: Image /qna-images/answer/0a76b54e-f0e2-4b93-a2bd-3ff079cfb064.jpg

A velocity field with no components in the yand z direction is given by: V = 6 + 2ry + t2. The acceleration along the x-direction at a point (3, 1, 2), at time 2, is: (a) 8 units (b) 16 units (c) 28 units (d) 36 units

A velocity field with no components in the yand z direction is given by: V = 6 + 2ry + t2. The acceleration along the x-direction at a point (3, 1, 2), at time 2, is: (a) 8 units (b) 16 units (c) 28 units (d) 36 units

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The position of a particle moving along the x-axis is given by (X(t)=3t+2t^3 ). Find the acceleration a= 3+6t^2 ( m/sec2) 12 (m/sec2) 12 t ( m/ssec2) Object's mass is 15 kg is resting on a table. An external force ( 10 N) act with angle ( 30) on this object. Find the minimum force let it moving. ( g=10m/sec2) * 5 N 150 N 8.66 N
A steady, incompressible, two-dimensional velocity field is given by the following components in the x-y plane: u = 1.85 +2.05x+0.656y v = 0.754 - 2.18x - 2.05y . Calculate the acceleration field (find expressions for acceleration components ax and ay), and calculate the acceleration at the point (x,y) = (0, 2). The acceleration components are ax= X ay y Acceleration components at (0, 2) are ax ay=
3Q. As a fluid flows through the fixed curved conduit in the figure shown, the velocity of particles is described by V = (0.4 s²) e 0.04 m/s, where s is in meters and t is in seconds. Determine the magnitude of the acceleration of the fluid particle located at point A, where s = 0.6 m, and the time of arrival is t = 1 s. The radius of curvature of the streamline at A is R = 0.5 m. s = 0.6 m 4
Q1 : The position of a particle moving along the x-axis is given by X =4t -9 calculate the acceleration and displacement if velocity 1m/sec
A steady, incompressible, two-dimensional velocity field is given by the following components in the x-y plane: u = 1. 85 + 2.05x + 0. 656y v = 0.754 – 2. 18x – 2.05y . Calculate the acceleration field (find expressions for acceleration components ax and ay), and calculate the acceleration at the point (x,y) = (0, 2). The acceleration components are ax = ay= Acceleration components at (0, 2) are ax= ay=
The 2.4kg particle moves in the horizontal x-y plane and has the velocity shown at time t=0. If theforce F = 2+3t^2/4 N, where t is time in seconds, is applied in the particle in the y-direction beginning attime t = 0, determine the velocity of the particle 4s after F is applied and specify the corresponding anglemeasured counter clockwise from the x-axis to the direction of the velocity
Q3: A particle moves along the x- axis according to the equation (x-14-7t+t^2+t^3 ), where (x) in meter and (t) in seconds. At (t=7 sec) Find (a) The position of the particle (b) It's velocity (c) It's .acceleration
DIPO Determine the slope at point B of the beam in the figure below. Assume the material's modulus of elasticity is 180 GPa, the beam's moment of inertia 360x10 mm4. 00 20 kN D 3 m 3 m 6 m A - I E=180 II !!
3- A steady, incompressible, two-dimensional velocity field is given by the following components in the xy-plane: u = 0.205 +0.97x+0.851y; v=v₁ +0.5953x -0.97y Calculate the acceleration field (find expressions for acceleration components ax and ay) and calculate the acceleration at the point (x, y)-(2, 1.5). vo=-1.150
The topic is all about the Angular Motion of Particles. Please use pen and paper to solve and also use three decimal places. Please show the conversion solution. Thank you. Here are the formulas: θ=θ_o+ω_o t+1/2 αt^2 ω=ω_0+αt ω^2=ω_o^2+2α(θ-θ_o) considering the tangential and normal components of the acceleration in a curvilinear motion of particles: a_t=rα a_n=rω^2=vω The angular motion may be derived from the translational motion of particles by considering the given circle: s=rθ ds/dt=r dθ/dt or v=rω dv/dt=r dω/dt or a=rα
The position of a particle moving along the x-axis is given by x=t^3+3t^2 -9t-6, when t =1sec particle is 11m to the right of origin. (a) When t=2 sec, determine v and a. (b)During the time interval from t=0 to t=2sec, determine the v(ave) and v(ave )speed
b) Uniform streams of fluid cross the boundary of a control volume containing a solid object. Briefly explain how Newton's 2nd and 3rd laws allow the resultant force vector acting on the body to be derived. Figure 2 shows a steady, uniform two-dimensional jet of liquid in the atmosphere impinging on a flat plate inclined at an angle q to the jet axis. The jet cross section area is A, and its velocity is u. The liquid density isr. It is assumed that there are no flow losses, and that all the streamlines end up parallel to the plate. Explain why the resultant force acts perpendicular to the plate, and show that its magnitude is: R22. A.u cosa Figure 2 A