A titration of 29.2 mL of a solution of the weak base aniline, C_HẠNH, ( K-4.0 x 10-10), requires 21.61 mL of 0.155 M HCI to reach the equivalence point. C_H_NHz(aq)}+HJO* (aq)=C_H_NH, (aq)+H_O() a What was the concentration of aniline in the original solution? Concentration = 0.315 The equivalence point for a reaction is the point at which one reactant has been completely consumed by addition of another reactant. Thus, [C HÌNH, X 0.155 mol HC1 1.00 L 1 29.2 mL <= 0.115 M x 21.61 ml x b what are the concentrations of H₂O*, OH, and CeHs NHS at the equivalence point? [H₂O+]- Correct M 1 mol C₂ H₂NH₂ 1 mol HC1 X Show Hint Previous Next>
A titration of 29.2 mL of a solution of the weak base aniline, C_HẠNH, ( K-4.0 x 10-10), requires 21.61 mL of 0.155 M HCI to reach the equivalence point. C_H_NHz(aq)}+HJO* (aq)=C_H_NH, (aq)+H_O() a What was the concentration of aniline in the original solution? Concentration = 0.315 The equivalence point for a reaction is the point at which one reactant has been completely consumed by addition of another reactant. Thus, [C HÌNH, X 0.155 mol HC1 1.00 L 1 29.2 mL <= 0.115 M x 21.61 ml x b what are the concentrations of H₂O*, OH, and CeHs NHS at the equivalence point? [H₂O+]- Correct M 1 mol C₂ H₂NH₂ 1 mol HC1 X Show Hint Previous Next>
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter14: Equilibria In Acid-base Solutions
Section: Chapter Questions
Problem 74QAP: Fifty cm3 of 1.000 M nitrous acid is titrated with 0.850 M NaOH. What is the pH of the solution (a)...
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![A titration of 29.2 mL of a solution of the weak base aniline,
C@HNH, (
K 4.0 x 10-10), requires 21.61 mL of 0.155 M
HCl to reach the equivalence point.
CH_NHz(aq) + HyO* (aq) + C,H,NH, (aq)+H,O(l)
a What was the concentration of aniline in the original solution?
Concentration 0115
✔ M
The equivalence point for a reaction is the point at which one reactant has been completely consumed by addition of another
reactant. Thus,
[C,HNH]
[H₂O+]
[OH-]-
=
0.155 mol HC1
1.00 L
1
29.2 mL
b What are the concentrations of
H₂O¹,
OH, and
C6H5NHs at the equivalence point?
M
C
= 0.115 M
x 21.61 ml x
M
Correct
1 mol C, H, NH,
1 mol HCl
Show Hint
<Previous
Next
Sava and E](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3c88ce79-7aca-47c1-8b60-1cd801e47e14%2F9a03707d-1188-488a-8523-248ec8b69d80%2Fsam4lzf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A titration of 29.2 mL of a solution of the weak base aniline,
C@HNH, (
K 4.0 x 10-10), requires 21.61 mL of 0.155 M
HCl to reach the equivalence point.
CH_NHz(aq) + HyO* (aq) + C,H,NH, (aq)+H,O(l)
a What was the concentration of aniline in the original solution?
Concentration 0115
✔ M
The equivalence point for a reaction is the point at which one reactant has been completely consumed by addition of another
reactant. Thus,
[C,HNH]
[H₂O+]
[OH-]-
=
0.155 mol HC1
1.00 L
1
29.2 mL
b What are the concentrations of
H₂O¹,
OH, and
C6H5NHs at the equivalence point?
M
C
= 0.115 M
x 21.61 ml x
M
Correct
1 mol C, H, NH,
1 mol HCl
Show Hint
<Previous
Next
Sava and E
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