/A Television signal having a bandwidth of 10.2 MHz is transmitted using binary PCM system. Given that the number of quantization levels is 512. Determine: (C) Code word length. (D) Transmission bandwidth. (E) Minimum required sampling rate.
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- Consider error control methods in digital signal transmission. Assume Hamming code is used with even parity. (a) Assume the received code word is 1110101001, determine if the code word is correct. If no, identify the wrong bit and obtain the original data word. (b) If the analogue signal before digitalisation is of frequency from 200 Hz to 1.5k Hz. What is the lowest sampling frequency? (c) Following (a) (b), determine the bandwidth requirement for transmitting the digital message.Problem 2: The information in an analog signal voltage waveform is to be transmitted over a PCM system with an accuracy of ± 0.1 % of the peak-to-peak analog signal. The analog voltage waveform has a bandwidth of 100 Hz and an amplitude range of – 10 to + 10 Volts. Determine the minimum sampling rate required. b. Determine the number of bits in each PCM word. c. Determine the minimum bit rate required in the PCM system. d. Determine the minimum absolute channel bandwidth required for the transmission of the PCM signal.(3) Five telemetry signals, each of bandwidth 1kHz, are to be transmitted simultaneously by binary PCM. The maximum tolerable error in sample amplitudes is 0.2% of the peak signal amplitude. The signals must be sampled at least 20% over the Nyquist rate. Framing and synchronizing require an additional 0.5% extra bits. Determine the minimum possible data rate that must be transmitted, and the minimum bandwidth required to transmit this signal.
- 1. With the help of Octave program perform the Modulation and Demodulation (AM) of information signal with carrier signal, through subplots with following signals a. Modulating signal b. Modulated signal c. Demodulated signalEx (3):- A signal that has the highest frequency component of 4.2MHZ and a peak to peak value of 4 volts is transmitted using a binary PCM. The number of quantization levels is 512 and P=0.04W calculate: 1. Code word length. 2. Bite rate.The information in an analog waveform, whose maximum frequency fm-4000Hz, is to be transmitted using a 16-level PAM system. The quantization must not exceed #1% of the peak-to peak analog signal. (a) What is the minimum number of bits per sample or bits per PCM word that should be used in this system? (b) What is the minimum required sampling rate, and what is the resulting bit rate? (c) What is the 16-ary PAM symbol Transmission rate?
- Explain the relationship between bits per second and baud for an FSK system. Define the following terms for FSK modulation: frequency deviation, modulation index, and deviation ratio. Explain the relationship between (a) the minimum bandwidth required for an FSK system and the bit rate and (b) the mark and space frequencies.For a FM system, the maximum freq deviation is 75 kHz and the maximum freq of the info. signal is 10 kHz. What will be the total bandwidth of the FM system? What will be the modulation index?A 450 kHz carrier signal is modulated with a 15 kHz modulating signal. What are its sideband frequencies?
- Determine (a) the bit rate and (b) the resolution in the sampling of a seismic signal with dynamic range of 1 volt if the sampling rate is and we use an 8-bit A/D converter. (c) What is the maximum frequency that can be present in the resulting digital seismic signal? (d) If this were to be a PCM system, calculate the minimum system bandwidth required.4. What parameter of a PPM signal varies in direct proportion to the message signal amplitude? a. the average frequency of the PPM pulses b. the distance between the PPM pulses c. the amplitude of the PPM pulses d. the width of the PPM pulses 5. What is the function of the prefilter in a PTM modulation circuit? completely removes frequencies greater than 8 kHz a. completely removes the PTM signal's first replica b. frequencies c. filters the message signal d. partially reconstructs and amplifies the message signal 6. What advantage does a PPM signal have over a PWM signal? a. can be used for message signals greater than 5 kHz b. requires lower sampling frequency c. easier to demodulate d. requires less transmission power 7. Why does PTM require a higher sampling frequency than PAM? a. The amplitude of PTM signals is constant. b. There are more sidebands in the first replica of a PTM c. Signal than in a PAM signal. d. A sample/hold circuit requires a higher sampling frequency. e. There…Discuss how the original signal can be recovered perfectly from the output of the decoder. What are the advantages of PCM system over the other types of modulation systems?