A system is described by the block diagram given below. Investigate the regulator characteristics of this system for a unit ramp input.
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- A fault current limiter as shown in the figure, has L1 = 1 mH and a total impedance of j10 Q. If the system frequency is 60 Hz, a) Find the capacitor C. Thyristor pair b) Find the inductor L2. L2 DKQ2) Design a Bridge FWR to supply a load of (1002) with the waveform shown in figure from the main power supply of (220 Vrms). Find: - 1- The transformer turns ratio (a). VOlvolt) 2- The ripple voltage. Vm = 12 V 3- The Vdc value. 4- The RMS value of the output voltage. V(p.P) = 0.1 V 5- The ripple factor. 6- The value of capacitor filter. (assume ideal diodes) T = 0.01 sec. → t(sec.)A 500 MVA synchronous machine has H, = 5.6 MJ/MVA and a 1200 MVA machine has H₂ = 2.0 MJ/MVA. The two machines operate in parallel in a power station. What is the equivalent. H constant for the two, relative to a 100 MVA base?
- Q1: Two forces act on the hook shown in figure. Determine the magnitude and direction of the resultant using Parallelogram Law. 600 N (Ans. R=910.241 N, angle=50.328 with horizontal) 50 400 N 20Q1. following: For the circuit shown in figure (a). Let V1 = 10Vms, frequency 10KHZ. Draw the A. Impedance diagram. B. Voltages phasor diagram. C. Current phasor diagram. D. Measure the voltage across R1,R2, Vin, and the inductor using the ocillscope using PROTEUS software. E. Measure the voltage in R1, R2, and the inductor using DMMby using PROTEUS software. F. From the above measurments verify your result. R2 1K V1 VSINE R1 L1 2K 1000MGiven the system below, for a unit step input, determine the percentage overshoot **I need a step by step answer please :)
- Q-3 A Cockcroft-Walton type voltage multiplier has ten stages with capacitances, all equal to 0.1 µF. The supply transformer secondary voltage is 100 kV at a frequency of 60 Hz. If the load current to be supplied is 5 mA, find (a) the percentage ripple, (b) the regulation, and (c) the optimum number of stages for minimum regulation or voltage drop.A SERIES CIRCUIT CONSISTING OF AN 80- OHM RESISTOR, A 0.30 HENRY INDUCTOR AND A 50-uf (MICROFARAD) CAPACITOR IS CONNECTED TO A 120-VOLT 60+ CYCLE SOURCE C ALCULATE THE FOLLOWINC : (A.) EQUIVALENT IMPEDANC E OF THE CKT, (B.) CURRENT (c.) VOLTAGE DROPACROSS THE SEVERAL UNITS (D.) POWER AND POWER FACTOR,Please solve this 2 problems in detail Problem 1: Consider a step up converter with a resistive load of value R=10 Ohms. It is supplied by a DC power source of magnitude Vs=220 V. The switching frequency is 4 kHz and the duty cycle k is first set to 0.5 and the inductance used within the circuit has a value of L=20 mH. The switch is supposed to be ideal. Using the boundary conditions, the minimum and maximum load current values are equal to: Select one : a. 41.65A and 44.695A b. 43.32A and 44.695A c. None of these d. 43.32A and 47.85A Problem 2: A step up DC converter is used to control power flow from a DC votage Vs = 100V to a battery voltage E = 200V. The power transferred to the battery is 20 kw. The current ripple of the inductor is negligible. The duty cycle and the effective load resistance as seen from the input are respectively equal to: Select one: a. None of these b. 0.5, 0.5 Ohms c. 0.33, 0.5 Ohms d. 0.5, 0.33 Ohms
- please explain in detail how to arrive at these answers. I am not the best at using Kirchoff voltage law.Q2) A 3-phase, half-wave thyristor converter is connected through a voltage source 150 V as input voltage and used to supply resistive load of 10 2. Determine rsm voltage, rms current, ripple factor and dissipated power in the resistor R. If a = 45° and f = 50 Hz. %3D4. A CT with an excitation curve given in the figure has a rated current ratio of 500:5 A and a secondary leakage impedance of 0.1 +j0.5 ohms. Calculate the CT secondary output current and the CT error for the following cases: a.) The impedance of the terminating device is 4.9 +j 0.5 ohms and the primary CT load current is 400 A. b.) The impedance of the terminating device is 4.9 +j0.5 ohms and the primary CT load current is 1200A c.) The impedance of the terminating device is 14.9 + j 1.5 ohms and the primary CT fault current is 400 A. d.) The impedance of the terminating device is 14.9 + j 1.5 ohms and the primary CT fault current is 1200 A w 100 80 60 40 20 2 4 6 10 Secondary exciting amps-, Secondary exciting volts-E'