A student pipets 18 mL of a 0.0459 M solution of CaCl2 into a 100.00 mL volumetric flask and dilutes to the mark. What is the concentration of the resulting solution?

Q: A student pipets 17 mL of a lithium sulfate solution into a 274 mL volumetric flask and dilutes to…

A:

Q: If 49.2 g of NaI (MM = 149.89 g/mol) are added to a 500.0 mL volumetric flask, and water is added to…

A:

Q: Vinegar can be assayed to determine its acetic acid content. Determine the molarity of acetic acid…

A: Molarity is defined as number of moles of solute dissolved per litre of the solution.…

Q: A 0.3146 g sample of a mixture of NaCl(s) and KBr(s) was dissolved in water. The resulting solution…

A: The reaction involves the determination of the unknown ions in a solution as their insoluble salt…

Q: A 14.5 g sample of an aqueous solution of hydrobromic acid contains an unknown amount of the acid.…

A:

Q: The concentration of citric acid (H3C6H5O7) in citric fruits ranges from 0.005 M to 0.30 M. Consider…

A: Since concentration of citric acid = moles of citric acid / volume of solution in L  Hence moles of…

Q: A mixture of hydrochloric and sulfuric acids is prepared so that it contains 0.235 M HCl and 0.605 M…

A: Given:Molarity of  HCl = 0.235 MMolarity of H2SO4 = 0.605 MTotal volume = 273.1 mLMolarity of NaOH =…

Q: If 30.0 g of Nal (MM = 149.89 g/ mol) are added to a 500.0 mL volumetric flask, and water is added…

A: Concentration or Molarity of NaI in the resylting solution will be: = Number of moles of NaIVolume…

Q: If 50.0 g of CH₃OH (MM = 32.04 g/mol) are added to a 500.0 mL volumetric flask, and water is added…

A: Number of moles =50.0 g/32.04 g/mol                                      =1.56 mol

Q: A student wishes to determine the mass percentage of barium in a 2.016g sample. The student…

A:

Q: If 91.9 mL of a 2.17 M solution is diluted to a volume of 218.2 mL, what is the final molar…

A:

Q: If 5.00 grams of Aluminum ( 27.0 g/mol) are added to 250.0 ml of a 100.0 mM Iron (III) chloride…

A: Given,

Q: 4.What is the molarity of the resulting solution? . From 60 ml of a 1.6 M nickel phosphate solution,…

A: Given that : Volume of nickel phosphate solution (V1)= 60 mL Molarity of nickel phosphate solution…

Q: A 5.00-g sample of vinegar is titrated with 0.108 M NaOH. If the vinegar requires 39.1 mL of the…

A: Given: The mass of the vinegar=5.00 g The concentration of NaOH=0.108 M The volume of NaOH=39.1m…

Q: How many grams of NaCl would be needed to precipitate the Ag⁺ ions from 2.500 × 10² mL of a 0.0115 M…

A:

Q: A chemist needs 225 mL of 2.4 M HCl. What volume of 12 M HCl must be dissolved in water to form this…

A: To calculate the volume of a definite molarity of a solution required to prepare solution of other…

Q: A student pipets 11 mL of a 0.0155 M solution of CaCl2 into a 100.00 mL volumetric flask and dilutes…

A: Given,

Q: If 203 mL of water is added to 5.00 mL of 4.16 M KCI solution, what is the concentration of the…

A: • The values provided in the question are:-  i) Initial volume of KCl solution, V1 = 5.00 mL  ii)…

Q: A titration is performed to determine the amount of sulfuric acid, H2SO4, in a 4.30 mL sample. About…

A:

Q: What is the concentration of nitric acid in the final solution?

A:

Q: Consider the reaction: Ag⁺(aq) + Cl⁻(aq) → AgCl(s) How many grams of NaCl would be needed to…

A: Please find your solution below :

Q: If 40.1 g of CH;OH (MM = 32.04 g/ mol) are added to a 500.0 mL volumetric flask, and water is added…

A:

Q: If 25.0 g of KBr (MM = 119.00 g/ mol) are added to a 500.0 mL volumetric flask, and water is added…

A: To determine concentration we have to find the number of moles and volume also. There is various…

Q: In the laboratory, a student adds 45.1 mL of water to 10.6 mL of a 0.773 M hydrobromic acid…

A: Given : Initial concentration of hydrobromic acid i.e HBr = 0.773 M Initial volume of HBr solution =…

Q: If 17.0 g of NaI (MM = 149.89 g/mol) are added to a 500.0 mL volumetric flask, and water is added to…

A: Given, the amount of NaI =17.0 grammolar mass of NaI =149.89 g/molvolume of solution =500.0 mL =0.5…

Q: A titration is performed to determine the amount of sulfuric acid, H2SO4, in a 6.43 mL sample taken…

A:

Q: A 10.0 mL sample of Potassium iodide solution was analyzed by adding an excess of Silver nitrate…

A: The balanced molecular equation for the reaction between Potassium iodide and Silver nitrate is…

Q: A 50.00-mL sample of aqueous Ca(OH)2 requires 34.66 mL of 0.917 M nitric acid for neutralization.…

A:

Q: mixture contains Mg(NO₃)₂ and KBr. A 1.85 g sample of this mixture is dissolved in water and an…

A: Given: Weight of sample containing  Mg(NO₃)₂ and KBr =1.85 g The mass of the precipitate = 0.475 g…

Q: Suppose you took a 3.00 mL sample of HNO3 (aq) of an unknown concentration, and find that you have…

A: Given: Volume of HNO3 = 3.00 mL Volume of NaOH solution = 20.30 mL Molarity of NaOH solution = 0.106…

Q: A 1.480 g sample of oxalic acid, H2C204, is placed in a 100.0-mL volumetric flask, which is then…

A: Given : Mass of oxalic acid = 1.480g

Q: A laboratory custodian needed to prepare 4590 mL of a 2.45 N solution of HCl for the conduct of…

A:

Q: A solution of MgSO4 (120.37 g/mol) is prepared by measuring 4.56 g of MgSO4 and diluting to a final…

A: Given, mass of MgSO4 = 4.56 g  Molarity = ?

Q: Consider the reaction: Ag⁺(aq) + Cl⁻(aq) → AgCl(s) How many grams of NaCl would be needed to…

A: According to the reaction: Ag⁺(aq) + Cl⁻(aq) → AgCl(s) 1 mol of Ag+ ion needs 1 mol of NaCl to…

Q: 200.0 mL of 3.96 M hydrochloric acid is added to 100.0 mL of 4.60 M barium hydroxide. After the…

A: Molar concentration of hydrochloric acid = 3.96 M Volume of hydrochloric acid = 200 ml = 0.2 L Molar…

Q: If 36.0 g of NaOH (MM = 40.00 g/mol) are added to a 500.0 mL volumetric flask, and water is added to…

A: Solution:               The concentration of solution gives the number of moles of solute dissolved…

Q: If 30.0 g of NaI (MM = 149.89 g/mol) are added to a 500.0 mL volumetric flask, and water is added to…

A:

Q: If 20.6 g of Nal (MM = 149.89 g/ mol) are added to a 500.0 mL volumetric flask, and water is added…

A: Molarity is a term used for concentration which shows the moles of solute dissolved per litres of…

Q: if 34.1g of Nal (MM= 149.89g/mol) are added to a 500.0mL volumetric flask, and water is added to…

A:

Q: 252 mL of 3.00 M H2SO4(aq) are added to 1.50 L of 0.500 M H2SO4(aq). What is the concentration of…

A: Concentration in terms molarity of is defined as the number of moles of solute present in per litre…

Q: CrCl3(s) + AgNO3 (aq)  AgCl(s) + Cr(NO3)3(aq) A 0.810 g sample of impure CrCl3 was dissolved in…

A: Given data,Molarity of AgNO3=0.165MVolume of AgNO3=45.5mL=0.0455LMass of impure CrCl3=0.810g

Q: A student pipets 18 mL of a lithium sulfate solution into a 264 mL volumetric flask and dilutes to…

A: Given, Volume of lithium sulfate  pipetted out = 18 mL volume of flask = 264 mL Final concentration…

Q: If 26.8 g of KBr (MM = 119.00 g/ mol) are added to a 500.0 mL volumetric flask, and water is added…

A: Mass of KBr = 26.8 gm

Q: A 1.280 g sample of oxalic acid, H2C2O4, is placed in a 100.0-mL volumetric flask, which is then…

A:

Q: the concentration of CH₃OH in the resulting solution?

A: Given,   Mass of CH3OH = 40.7 g Molar mass of CH3OH = 32.04 g/mol According to problem volume of…

Q: A student pipets 18 mL of a lithium sulfate solution into a 164 mL volumetric flask and dilutes to…

A: We have to calculate the concentration of the original solution.

Q: A mixture contains Mg(NO3)2 and KBr. A 1.85 g sample of this mixture is dissolved in water and an…

A:

Q: A student weighs out a 16.7 g sample of Ba(CH3COO)2 , transfers it to a 300. mL volumetric flask,…

A: Molarity (M) can be defined as the moles of solute that can be dissolved per litre of solution. It…

Q: Consider the following unbalanced equation: Zn (s) + HCl (aq) → ZnCl2 (aq) + H2 (g) What…

A: Given,  Zn (s) + 2HCl (aq) → ZnCl2 (aq) + H2 (g) Mass of Zn= 0.5065 g  Molarity of HCl= 0.1260 M…

Q: A 8.84 g sample of an aqueous solution of hydrobromic acid contains an unknown amount of the acid.…

A: