A stepped bar is held in equilibrium by several forces acting at different points along the length, as shown in the figure below. The magnitudes for three of the forces are F2 = 39 kN, F3 = 11 kN, and F4 = 12 kN. All forces act parallel to the axis of the bar, and both pairs of forces F2 and F3 are located the same distance from the centerline of the bar. Determine the internal normal forces (P) at points A, B, and C.

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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A stepped bar is held in equilibrium by several forces acting at different points along the length, as shown in
the figure below. The magnitudes for three of the forces are F₂ = 39 kN, F3 = 11 kN, and F4 = 12 kN. All
forces act parallel to the axis of the bar, and both pairs of forces F2 and F3 are located the same distance from
the centerline of the bar. Determine the internal normal forces (P) at points A, B, and C.
Note: Express tension forces as positive (+) and compression forces as negative (-).
F₁₂
PA =
PB
Pc =
=
F₂
A:
F₂
number (rtol=0.01, atol=1e-05)
number (rtol=0.01, atol=1e-05)
number (rtol=0.01, atol=1e-05)
B
kN
kN
kN ?
?
F₂
F₂
C.
F₁
Transcribed Image Text:A stepped bar is held in equilibrium by several forces acting at different points along the length, as shown in the figure below. The magnitudes for three of the forces are F₂ = 39 kN, F3 = 11 kN, and F4 = 12 kN. All forces act parallel to the axis of the bar, and both pairs of forces F2 and F3 are located the same distance from the centerline of the bar. Determine the internal normal forces (P) at points A, B, and C. Note: Express tension forces as positive (+) and compression forces as negative (-). F₁₂ PA = PB Pc = = F₂ A: F₂ number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol=1e-05) B kN kN kN ? ? F₂ F₂ C. F₁
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