A spring fixed at the upper end supports a weight of 980 gm at its lower end. The spring stretches cm under a load of 10 gm and the resistance (in gm wt.) to the motion of 2 the weight is numerically equal to of the speed of the weight in cm/sec. The weight is pulled down ! Find the expression for the distance of weight from its equilibrium position at time t during its first upward motion. 10 cm. below its equilibrium position and then released. to Also find the time it takes the damping factor to drop to of its initial value. 1 10
A spring fixed at the upper end supports a weight of 980 gm at its lower end. The spring stretches cm under a load of 10 gm and the resistance (in gm wt.) to the motion of 2 the weight is numerically equal to of the speed of the weight in cm/sec. The weight is pulled down ! Find the expression for the distance of weight from its equilibrium position at time t during its first upward motion. 10 cm. below its equilibrium position and then released. to Also find the time it takes the damping factor to drop to of its initial value. 1 10
International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter7: Dry Friction
Section: Chapter Questions
Problem 7.78P: The figure shows a steel bar being processed by a rolling mill. Given that P=80kN and r =0.016,...
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