A solid sphere of mass, M = 5.0 kg, and radius, R = 0.100 m is placed on two blocks so that it’s centre of mass lies at the origin as shown on the right. A bullet of mass, m = 0.100 kg, and with an x coordinate of b = 0.04 m strikes the sphere from below with a vertical velocity, v = 65 m/s and embeds in the sphere coming to rest at the location (-b,0) in the diagram below. Since there is no momentum in the horizontal direction, after the bullet hits the sphere , it will rise up to some maximum height and then fall back to its initial position on the two blocks. While the sphere is in the air it will rotate. What is the magnitude of the angle (in degrees) through which the sphere will rotate before it makes contact with the two blocks again?
A solid sphere of mass, M = 5.0 kg, and radius, R = 0.100 m is placed on two blocks so that it’s centre of mass lies at the origin as shown on the right. A bullet of mass, m = 0.100 kg, and with an x coordinate of b = 0.04 m strikes the sphere from below with a vertical velocity, v = 65 m/s and embeds in the sphere coming to rest at the location (-b,0) in the diagram below. Since there is no momentum in the horizontal direction, after the bullet hits the sphere , it will rise up to some maximum height and then fall back to its initial position on the two blocks. While the sphere is in the air it will rotate. What is the magnitude of the angle (in degrees) through which the sphere will rotate before it makes contact with the two blocks again?
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