A small ball of mass m=3.60×10−12 kg has acquired an excess charge. The ball is then placed between two parallel plates spaced x=0.00360 m apart, which have a potential difference of V=2110 V applied across them. In this configuration, the ball appears to be motionless, or floating in between the plates. What is the overall charge on the ball? Calculate the number of electrons, ne, that the ball has either gained or lost. The acceleration due to gravity is g=9.81 m/s2, and the elementary unit of charge is ?=1.60×10−19 C.
A small ball of mass m=3.60×10−12 kg has acquired an excess charge. The ball is then placed between two parallel plates spaced x=0.00360 m apart, which have a potential difference of V=2110 V applied across them. In this configuration, the ball appears to be motionless, or floating in between the plates. What is the overall charge on the ball? Calculate the number of electrons, ne, that the ball has either gained or lost. The acceleration due to gravity is g=9.81 m/s2, and the elementary unit of charge is ?=1.60×10−19 C.
Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter25: Electric Potential
Section: Chapter Questions
Problem 25.1OQ: In a certain region of space, the electric field is zero. From this fact, what can you conclude...
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A small ball of mass m=3.60×10−12 kg has acquired an excess charge. The ball is then placed between two parallel plates spaced x=0.00360 m apart, which have a potential difference of V=2110 V applied across them. In this configuration, the ball appears to be motionless, or floating in between the plates.
What is the overall charge on the ball?
Calculate the number of electrons, ne, that the ball has either gained or lost. The acceleration due to gravity is g=9.81 m/s2, and the elementary unit of charge is ?=1.60×10−19 C.
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