A shaft subjected to torsion experiences a pure shear stress t on the surface. The maximum principal stress on the surface which is at 45° to the axis will have a value (a) t cos 45° (b) 2t cos 45° (d) T COSs2150 (d) 2T sin 45° cos 459
Q: 4. Given a shear stress of T-35 MPa and a shear modulus of G= 75 GPa, the shear strain is most…
A: Given data Shear stress=35 mpa Shear modulus =75 gpa We have to determine shear Strain
Q: 3. If o, = 30 ksi, o, = 20 ksi, and ty = 10 ksi, what is the maximum in-plane shear stress in ksi? →…
A: Given:σx=30 ksiσy=20 ksiζxy=10 ksi
Q: Oy Txy
A: given; normal stress in x direction =σxnormal stress in y direction =σyshear stress in xy…
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A: find the maximum shear stress in the shaft.
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Q: 10 MPа 4 ksi 10 MPа 4 ksi 10 MPа 2 ksi
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A: As given in the question, Maximum principal stress = σ1 = 100 MPa Minimum principal stress = σ2 = 40…
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A: From the given figure, σx = 100 MPa σy = 80 MPa τxy = 50 MPa
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A: Given Dataσx=15ksiσy=12ksiσz=11ksiτxy=3ksiτyz=-4ksiτzx=0θ1=41°θ2=61°θ3=63.77°
Q: 0. A pressure vessel containing gas at 250 psi has an outer diameter of 12 inches and a thickness of…
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Q: Listed below is a combination of stresses acting at a point and referred to axes x and y in an…
A: As Given in case (1); σx= -60 N/mm2 , σy= -36 N/mm2 , ζxy= 5 N/mm2 So the principal stresses will be…
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Q: The state of plane-stress at a point is given by σx = -200 MPa, σy = 100 MPa and txy = 100 MPa The…
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Q: A shaft subjected to torsion experiences a pure shear stresst on the surface. The maximum principal…
A: Given: A shaft subjected to torsion,θ=45o
Q: 3. Listed below is a combination of stresses acting at a point and referred to axes x and y in an…
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Q: Calculate the normal stress and shear stress acting on the plane 2x+y+2z=1 passing thorough a point…
A: given; plane ;2x+y+2z=1stress at point (σ)=162022000023
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Q: 2.6. The principal stresses at a given point are ơ1 =10 ksi, o2 =5 ksi. Sketch Mohr's circle for…
A: givenσ1=10ksiσ2=5ksi
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- -27 A square plate with side dimension of 2 in. is subjected to compressive stress a and tensile stress The stresses on element A oriented at angle ?? x1=45° aresy1= 75 psi. tx1y1= 275 psi. . Find the state of stress on the element lilt is rotated clockwise to align the x3 axis with the horizontal x axis.An clement m plane stress from the frame of a racing car is oriented at a known angle 8 (sec figure). On this inclined clement, the normal and shear stresses have the magnitudes and directions shown in the figure. Determine the normal and shear stresses acting on an clement whose sides are parallel to the \y axes, that is, determine crv, tr(_, and t, Show the results on a sketch of an clement oriented at B .At a point on the surface of an elliptical exercise machine, the material is in biaxial stress with t = 1400 psi and trv = —900 psi, as shown in the figure part a. The figure part b shows an inclined plane aa cut through the same point in the material but oriented at an angle ft Determine the value of the angle 6 between zero and 90° such that no normal stress acts on plane aa. Sketch a stress clement having plane aa as one of its sides and show all stresses acting on the clement
- A shaft subjected to torsion experiences a pure shear stresS t on the surface. The maximum principal stress on the surface which is at 45° to the axis will have a value (a) t cos 45° (b) 2t cos 45° (d) t cos? 45° (d) 2t sin 45° cos 45°The state of stress at a point under plane stress 40 MPa, Oyy condition is Ox = = 100 MPa and Txy 40 MPa. This radius the Mohr's circle representing the given state of stress in MPa is:The state of stress at a point in a machine component is given by ox = 120 MPa, oy = 55 MPa, Oz = -85 MPa, Oxy = -55 MPa, Oxz = -75 MPa, and oyz = 33 MPa. Construct the Mohr's circles of stress for this stress state and find the maximum shear stress.
- In a plane stress condition, the components of stress at point are ox = 20 MPa, ơy = 80 MPa and Txy = 40 MPa. The maximum shear stress (in MPa) at the point isThe distribution of stress in an isotropic aluminium machine component is given (in MPa) as: σ₂ = y +2z² - 6 σ₁ = x+z-6 oy σ₂ = 3x+y-13 6: T =3z² -11 xy (i) (ii) =x²-14 Tyz Txz = y² XZ x, y and z are coordinates of a point within the machine component. By taking Young's modulus, E = 70 GPa, Poisson ratio, v= 0.3 and yield stress, Y = 5 MPa, do the following for a point P located at (4, 1, 2): a) Provide the stress and strain tensors. b) Determine all the principal stresses and principal strains. c) Determine if the machine component will fail based on the failure criteria below: Tresca criterion Von Mises criterionThe state of plane stress at a point is represented by the element shown in the figure. Oy o, = 200 Mpa oy = 450 Mpa Txy Try 3D200 Мра Click here to see all formulas Ox Part A - Determine the maximum principal stress in Mpa. O 253 О 355 O 507 O 760 O 608 Submit Request Answer O O O O O
- A piston-cylinder has a force F₁ applied to it. The circumferential stress in the cylinder cannot exceed Omax = 6 MPa. Hint: 1. Pressure = F Area P = F₁ F₁- OG Values for the figure are given in the following table. Note the figure may not be to scale. Variable Value T'inner 44 mm t 1.25 mm r1 a. Determine the max pressure that the piston-cylinder can withstand, P. b. Determine the magnitude of max force that can be exerted on the piston to not exceed omax, F1. kPa NA plane stress state is given by the principal stresses σx =25 MPa and σy= -11 MPa. Determine σx' in the case that the system is inclined by 30 degrees (counter-clockwise). Give your answer in MPa to the nearest whole number.Q1/ For the state of plane stress shown below, construct a Mohr's circle and determine:- (a) the principle stress acting at this point (b) the orientation of the principle stress (c) the maximum in-plane shear stress at the point and the corresponding average normal stress (d) the orientation of the maximum in-plane shear stress (e) show the results on elements 700 kPa 100 kPa tal stress enks 400 kPa