Solution added A seismic survey was carried out for a large project to determine the nature of the substrata. Theresults of the survey are given in Fig. i2 in the form of a graph. Determine the depths of thestrata.V, = 2250 m/secx 5 x 10C,Surface soilV = 750 m/secSand and loose gravelV,RockAB, = 8.75 x 10'secAC, 33.75 x 10 secAC: = 38.75 x 10 secd; = 2.188 md = 22.5 mAB = 12,75 x 10 secV = 172 m/sec1020 d;304050Distance mFigureTime of first wave arrival, seconds

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A seismic survey was carried out for a large project to determine the nature of the substrata. The results of the survey are given in Fig. i in the form of a graph. Determine the depths of the strata. V = 2250 m/sec 8 x 5 x 10 Surface soil V = 750 m/sec Sand and loose gravel H V, Rock AB, = 8.75 x 10' see AC, = 33.75 x 10' sec AC: = 38.75 x 10 sec B d, = 2.188 m d; = 22.5 m AB = 12.75 x 10 scc V = 172 m/sec 10 20 d; 30 40 50 Distance m Figure Time of first wave arrival, seconds

A seismic survey was carried out for a large project to determine the nature of the substrata. The results of the survey are given in Fig. i in the form of a graph. Determine the depths of the strata. V = 2250 m/sec 8 x 5 x 10 Surface soil V = 750 m/sec Sand and loose gravel H V, Rock AB, = 8.75 x 10' see AC, = 33.75 x 10' sec AC: = 38.75 x 10 sec B d, = 2.188 m d; = 22.5 m AB = 12.75 x 10 scc V = 172 m/sec 10 20 d; 30 40 50 Distance m Figure Time of first wave arrival, seconds

Principles of Foundation Engineering (MindTap Course List)

9th Edition

ISBN:9781337705028

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter3: Natural Soil Deposits And Subsoil Exploration

Section: Chapter Questions

Problem 3.6P

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Q.13.3 A seismic survey was carried out for a large project to determine the nature of the substrata. The results of the survey are given in Fig. i in the form of a graph. Determine the depths of the strata. V, = 2250 m/sec 8 x5 x 10 V, Surface soil . V = 750 m/sec Sand and loose gravel H V, Rock AB, = 8.75 x 10 sec AC, = 33.75 x 10' sec AC: = 38.75 x 10 ' sec di = 2.188 m = 172 m/sec d; = 22.5 m AB = 12.75 x 10' sec 0 d 20 d 30 Distance m 10 40 50 Time of first wave arrival, seconds 6o
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