A researcher must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures: 90.8 60.9 76.2 46.1 80.9 Assuming the population of temperatures are normally distributed, find the 80% confidence interval. Round the answers to two decimal places. Enter your answer as an interval of the form (LB, UP). The researcher is 80% confident that the population average temperature is within the temperature interval

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A: Since there are multiple sub-parts, as per the honor code the first three sub-parts will be solved.…

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A: As per bartleby guidelines we can solve only first three subparts and rest can be reposted

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Q: find the 99% confidence interval of the mean number of miles driven per day by all truckers

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A: Given  y^=4.3-14.9x  Objective has to be test the negative relationship between x and y.

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A: Solution-: Let, X=Year and  Y=The high temperature Given data: X Y 4 18.34 5 20.1 6 20.06…

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A: Given confidence interval is 14<μ<25.1sample size(n)=18

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A: Given that  n = 800 , p^ = 0.78

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A: Given data: Beginning End 53.82 54.19 77.02 55.7 109 102.57 83.58 79.95 139.23 126.01…

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Q: B-25 Determine the sample size for each of the control procedures shown in the following table…

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Q: For a binomial distribution with a sample size equal to 8 and a probability of a success equal to…

A: given data, n=8p=0.24q=1-p=1-0.24=0.76x= no. of successp(X=x)=nCx*px*q(n-x)   (binomial…

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A: From the provided information, Mean (µ) = 39.4 Standard deviation (σ) = 52.5 X~N (39.4, 52.5)

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A:

Q: SAT exam scores are normally distributed with μ = 500 and σ = 100. Use your calculator to find the…

A: We have given that  Mean(µ) = 500Standard deviations (σ) = 100X ~ N (µ, σ )= N(500, 100)

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A: Given that p^=0.64α=0.05 sample=130

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